[填空题]
A particle revolves in a horizontal circle of radius 2.90 m . At a particuu4y5 b;m1iu) sbmpcr 5:gs3kila1qif8vm m/( .pwfbe9 wr invb mfm( w1/ep.qi98wfstant, its acceleration is 1.05 $\mathrm{~m} / \mathrm{s}^{2}$ , in a direction that makes an angle of 32.0$^{\circ}$ to its direction of motion. Determine its speed (a) at this moment
(b) 2.00 s later, assuming constant tangential acceleration.
