本题目来源于试卷: Continuity and Change D.1 DNA Replication，类别为 IB生物学
[单选题]
The table below shows the percentage of nitt:(zh;vx vvqvel;)ib;9 / :ddu;tw vsrogenous bs29lo h-g.db8 hrr( sngqw//nei2, ko ases found in the DNA of Escherichia cr-9/gld./srqnw,oeg (2hi hn 8bok2 soli bacteria.
Adenine Cytosine Guanine Thymine
32% 18% 18% 32%
What conclusion can be made based on the data shown in the table above?
A. There is complementary base pairing between adenine and thymine, and between cytosine and guanine
B. The total amount of cytosine and guanine is less because there are fewer hydrogen bonds between cytosine and guanine
C. The bacteria contain a circular chromosome which prevents errors when nitrogenous bases pair up
D. The percentage composition of base pairs found in chromosomes and plasmids is different
参考答案: A
本题详细解析:
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