[填空题]
The equation of a linr ;6lrwxgq ecwbv)e;796bw 4j .u/9 raac joao)5ft)nlv::+jn dwit9 e $ L_{1}$ is 2 x+3 y=-5 .
1. Find the gradient of $L_{1}$ .
A second line, $L_{2}$ , is perpendicular to $L_{1}$ .
2. State the gradient of $L_{2}$ .
The point $\mathrm{P}(4,0)$ lies on $L_{2}$ .
3. Find the equation of $L_{2}$ , giving your answer in the form a x+b y+d=0 , where a, b, d $\in \mathbb{Z}$ .
The point \mathrm{Q} is the intersection of L_{1} and L_{2} . y=
4. Find the coordinates of Q . (a,b) a = b =
