本题目来源于试卷: Trigonometric Functions，类别为 IB数学
[问答题]
Consider the equatio14g e6hqprm4bgfm) 2gj 9tg 2t wve /sbullb)64m: pgiv6b)l7n
$\frac{\sqrt{\sqrt{2}-1}}{\sin x}+\frac{\sqrt{\sqrt{2}+1}}{\cos x}=2 \sqrt[4]{8}, \quad 0 \lt x \lt\frac{\pi}{2}$ .
1. Given that $\sin \left(\frac{\pi}{8}\right)=\frac{1}{2} \sqrt{2-\sqrt{2}} $ and $\cos \left(\frac{\pi}{8}\right)=\frac{1}{2} \sqrt{2+\sqrt{2}}$ , verify that $x=\frac{\pi}{8}$ is a solution to the equation.
2. Hence find the other solution to the equation.
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