[填空题]
The potential differenc1+ bfz, acw-tctpt/r 9. fvmd5e ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (only put numerical values in the blank and keep two significant figures.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the smal 9c)as,9u )x d8:as( bhskyklplest value which(9)8 ssx b)k:kpld y9a ,sauch it can record, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.
