[填空题]
A force of 10.0 ± 0.2 N is applied to a massp p4aa55, tfps of 2.0 ± 0.01 kg, causing it to acca,p 5f4tap5 spknut h9 rbnlc3rp 4y.;nt3 e.;elerpr n4b c3t l3n.9 e.nyut;kh;rate. What is the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculatlp0i70u / sqghz*u nwo0 m,.sass 6oc/ed using the formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
