题库网 (tiku.one)

 找回密码
 立即注册

手机扫一扫,访问本页面

开启左侧

Physics Unit3: Kiematics Motion in Two Dimension & Vectors (id: 57264ece0)

[复制链接]
admin 发表于 2024-9-27 21:20:50 | 显示全部楼层 |阅读模式
本题目来源于试卷: Physics Unit3: Kiematics Motion in Two Dimension & Vectors,类别为 通用国际物理

本题为动态变量类型,下面题目描述与解答中出现的数值不同于您在作答时遇到的数值!

[填空题]
Vector A is 5.5 cm long :- mwe. nt ytd(.1bezjx ik4k5and points yfzxga))ti* 4 f, h(z6amdgxc9yx4j:kp/w+h along the positive x axis. Vector B is 7.5 cm long and g:hdzkca ) +fyyf,i6ta (/)4hpmxgzw94xx*jpoints at $+30^{\circ}$ to the negative x axis.
(a) Determine the x component of Vector A $A_x =$   $cm$ and y component of Vector A $A_y =$   $cm$
(b) Determine the x component of Vector B $B_x =$   $cm$ and y component of Vector B $B_y =$   $cm$
(c) Determine the sum of these two vectors in terms of components. $R_x=$    $cm$ and $R_y=$    $cm$
(d) Determine the sum of these two vectors in terms of magnitude    $cm$ and the tangent value of the direction angle (measured from the posive x axis rotated in the counterclock wise direction) $\tan \theta = $   
Please only fill in numerical values in the above blanks!




参考答案:
空格1: 5.5空格2: 0空格3: -6.5空格4: 3.75空格5: -0.995空格6: 3.75空格7: 3.88空格8: -3.77


本题详细解析: 暂无

微信扫一扫,分享更方便

帖子地址: 

回复

使用道具 举报

您需要登录后才可以回帖 登录 | 立即注册

本版积分规则

浏览记录|使用帮助|手机版|切到手机版|题库网 (https://tiku.one)

GMT+8, 2025-4-12 06:12 , Processed in 0.082347 second(s), 29 queries , Redis On.

搜索
快速回复 返回顶部 返回列表