[填空题]
A particle revolves in abpw5ixzf*45ea1 vxf *kxmk cm9w(, p7 horizontal circle of r3q2-3h 9wm5 pieow,( qiepr kpadius 2.90 m . At a particular instant, i9 riekep iqh,pm(-wqwo 52p 33ts acceleration is 1.05 $\mathrm{~m} / \mathrm{s}^{2}$ , in a direction that makes an angle of 32.0$^{\circ}$ to its direction of motion. Determine its speed (a) at this moment
(b) 2.00 s later, assuming constant tangential acceleration.