本题目来源于试卷: gc textbook chapter 11 Vibrations and Waves，类别为 IB物理学
[问答题]
When a sinusoidal wave crosse fw/iytdx p7rc 7e5e34s the bound 6ao,ysi n 4aco4ko0t +em,pz/ary between two sections of cord as in Fig. 11–33, the frequency does not change (although the wavelength and velocity do +4o cp,0kyoaa es ,znt6o/im4change). Explain why.
参考答案:
The frequency must stay the same because the media is continuous – the end of one section of cord is physically tied to the other section of cord. If the end of the first section of cord is vibrating up and down with a given frequency, then since it is attached to the other section of cord, the other section must vibrate at the same frequency. If the two pieces of cord did not move at the same frequency, they would not stay connected, and then the waves would not pass from one section to another.
本题详细解析:
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