[填空题]
A clock pendulum oscillates at a7 2/ vpow*ic. dd v r/)3eohjk.j)jfxa frequency of 2.5 Hz. At h+bv g8+qu(af it is released from rest starting at an u+q8(gfabhv+angle of 15 $^{\circ} $ to the vertical. Ignoring friction, what will be the position (angle) of the pendulum at
(a) t = 0.25 s , $^{\circ} $
(b) t = 1.60 s , $^{\circ} $
(c) t = 500 s ? $^{\circ} $
[Hint: Do not confuse the angle of swing $\theta$ of the pendulum with the angle that appears as the argument of the cosine.]