本题目来源于试卷: gc textbook chapter 12 Sound，类别为 通用国际物理
[问答题]
Explain how a tube might ber/ 0 pegt1y 7owv35k)bq 3sxcx used as a filter to red3;w4esf,:h*wf/ytlxcmx (9;m l h ywkuce the amplitude of sounds in various frequency ranges. (An exam:;wy/e; ktxlc,xmhwl wf*h9 4s3m f( yple is a car muffler.)
参考答案:
A tube of a given length will resonate (permit
standing waves) at certain frequencies.
When a mix of frequencies is input to the tube, only those frequencies
close to resonant frequencies will produce sound that persists, because standing
waves are created for those frequencies.
Frequencies far from resonant frequencies will not persist very long at
all – they will “die out” quickly. If,
for example, two adjacent resonances of a tube are at 100 Hz and 200 Hz, then
sound input near one of those frequencies will persist and sound relatively
loud. A sound input near 150 Hz would
fade out quickly, and so have a reduced amplitude as compared to the resonant
frequencies. The length of the tube can
be chosen to thus “filter” certain frequencies, if those filtered frequencies
are not close to resonant frequencies.
本题详细解析:
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