Particulate Nature of Matter B.5 Electric Circuits (id: e0963ee52)

本题目来源于试卷: Particulate Nature of Matter B.5 Electric Circuits，类别为 IB物理学

[单选题]
Two resistors, P and Q, demonstrate the following relationships between current I and potential difference V.


The resistors are arranged as follows.

If the ammeter reads a current of 3.0 $A$, what is the potential difference across the cell?

A. 0.75 V
B. 3 V
C. 5 V
D. 7 V


参考答案:  C


本题详细解析:
Explanation；

Because the components are in parallel, the current read by the ammeter is the sum of the currents through the resistors P and Q.

From the graph we see their combined current is 3.0$A$ at a potential difference of 5.0$V$.

This must be the potential difference that the cell supplies to the circuit.

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