本题目来源于试卷: Wave Behavior C.1 Simple Harmonic Motion，类别为 IB物理学
[单选题]
A mass M hangs in equilibrium on a spring. The mass is pulled down 10 $cm$ below the equilibrium position and released. It oscillates vertically about the equilibrium position performing simple harmonic motion.
If it takes 0.5 $s$ after release to return to its equilibrium position, which of the following is true for its first oscillation?
A. Amplitude (cm) is 10; Frequency (Hz) is 2
B. Amplitude (cm) is 20; Frequency (Hz) is 0.5
C. Amplitude (cm) is 10; Frequency (Hz) is 0.5
D. Amplitude (cm) is 20; Frequency (Hz) is 2
参考答案: C
本题详细解析:
Explanation: Since it is pulled down by 10 $cm$, that is the maximum displacement and hence the amplitude. If it takes 0.5 s to return to the equilibrium position, then the complete oscillation is (0.5)(4)=2s. Since $f=\frac{1}{T}$ and T=2s, frequency is 0.5$Hz$.
| 
