Wave Behavior C.1 Simple Harmonic Motion (id: b93156c46)

本题目来源于试卷: Wave Behavior C.1 Simple Harmonic Motion，类别为 IB物理学

[单选题]
A particle performs simple harmonty 8hx y36iw ;viy+u4.pkpbq4ic motion withke91 dg:1bv c ybkfx ;y1(ewz; a frequency of $0.05Hz$ The distance traveled by the particle in one complete oscillation is $16\,cm$ Which of the following graphs shows a correct variation of its position?

A.
B.
C.
D.


参考答案:  A


本题详细解析:

Explanation:

Since frequency is  0.05Hz,T=$\frac{1}{f}$=$\frac{1}{0.005}$=20s

The amplitude is 4cm on either side of the equilibrium position because in one full cycle it travels four amplitudes

($\frac{16}{4}=4cm$)

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