[单选题]
A particle performs simple harmonic motion with a f
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8 + k5e1ae8:g nu friknreq(v7uency of $0.05Hz$ The distance traveled by the particle in one complete oscillation is $16\,cm$ Which of the following graphs shows a correct variation of its position?

A.
B.
C.
D.
参考答案:
A
本题详细解析:
Explanation:
Since frequency is 0.05Hz,T=$\frac{1}{f}$=$\frac{1}{0.005}$=20s
The amplitude is 4cm on either side of the equilibrium position because in one full cycle it travels four amplitudes
($\frac{16}{4}=4cm$)