[单选题]
A particle performs simple
: bm6qm8*s3m4gzlm xeharmonic motion
olm1 jw7cp+5v with a frequency of $0.05Hz$ The distance traveled by the particle in one complete oscillation is $16\,cm$ Which of the following graphs shows a correct variation of its position?
A.
B.
C.
D.
参考答案:
A
本题详细解析:
Explanation:
Since frequency is 0.05Hz,T=$\frac{1}{f}$=$\frac{1}{0.005}$=20s
The amplitude is 4cm on either side of the equilibrium position because in one full cycle it travels four amplitudes
($\frac{16}{4}=4cm$)
