本题目来源于试卷: Nuclear & Quantum Physics E.2 Quantum Physics，类别为 IB物理学
[单选题]
Light from a sodium lampgs2r jxpcs ;an 93;y1q*zp ()qhalai-n sc39t of wavelength is direcv*71g* fysxvd6 ;dt80ic g aqhted towards a metal surface and electrons unti f 6svd*y8vt1 xh7qgi0g;*adcl a stopping potential of $V_s$ is applied. The wavelength of the incident light is halved. Which of the following corresponds to the new value of the required stopping potential?
A. $\frac{V_s}{2}$
B. $\frac{V_s}{2}$-$\frac{ϕ}{e}$
C. $2V_s$
D. $2V_s$+$\frac{ϕ}{e}$
参考答案: D
本题详细解析:
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