Models of Bonding & Structure B.2 The Covalent Model (id: 34a1f2390)

本题目来源于试卷: Models of Bonding & Structure B.2 The Covalent Model，类别为 IB化学

[单选题]

Molecules of liquid bromine trifluoride (BrF3)($BrF_3$) react with each other to form $BrF_2^+$ and $BrF_4^-$ ions.

Which equation shows the molecular and electron domain geometries of the reactant and products?

A.
B.
C.
D.


参考答案:  A


本题详细解析:
The $\mathrm{B}\mathrm{r}$ atom in $BrF_3$ has two lone pairs. The electron domain geometry of $BrF_3$ is trigonal bipyramidal, and the lone pairs occupy equatorial positions to minimize repulsion with each other and with the bonding electron pairs. Thus, the molecular geometry is T-shaped.
$\mathrm{B}\mathrm{r}\mathrm{F}{\phantom{}}_4{\phantom{}}^{-}$$BrF_4^-$ has four bonding pairs and two non-bonding pairs of electrons, so the molecular geometry is square planar and the electron domain geometry is octahedral.
This question is very hard, as the student must deduce both the number of non-bonding electrons on the Br atom and the geometry that will minimize repulsion between lone and bonding electron pairs.

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