本题目来源于试卷: Models of Bonding & Structure B.2 The Covalent Model，类别为 IB化学
[单选题]
The Lewis structure of the nitrite ion is shown.
What is the hybridization of the N atom and the most likely value of the bond angle in the nitrite ion?
A. Hybridization of N is $sp^2$;Bond angle \$^{\circ}$ is 125
B. Hybridization of N is $sp^2$;Bond angle \$^{\circ}$ is 115
C. Hybridization of N is $sp^3$;Bond angle \$^{\circ}$ is 112
D. Hybridization of N is $sp^3$;Bond angle \$^{\circ}$ is 107
参考答案: B
本题详细解析:
The N atom has three electron domains so is $sp^2$ hybridized. The $sp^2$ orbitals are occupied by two bonding pairs and one non-bonding pair of electrons. The repulsion between the non-bonding and bonding pairs is greater than that between the two bonding pairs, so the bond angle is less than the expected value of 120$^{\circ}$ ;115$^{\circ}$ is the most likely of the two options given.
This question is very hard as the student must correctly identify the hybridization of an unfamiliar molecule, in which one $sp^2$ orbital is occupied by non-bonding electrons rather than a bonding pair, and apply VSEPR principles to deduce the likely bond angle.
| 
