本题目来源于试卷: Classification of Matter A.1 Periodic Table Elements Classification，类别为 IB化学
[单选题]
The electron affinity of carbo1re op2 jcxs z( -)pnaqc09th)t2xj /gn inw/h4aa8qw 78 m7zqwp g(vv9 ss $-122\,kJ\,mol^{−1}$, whereas the electron affinity of boron is $-27\,kJ\,mol^{−1}$. Which statement below best explains this difference?
A. Carbon has more protons resulting in an increased attraction for its valence electrons
B. The electrons in boron are located in a lower energy level than carbon
C. Boron has fewer electrons than carbon
D. The trend decreases from left to right across the periodic table
参考答案: A
本题详细解析:
Explanation: The 6 protons in the nucleus of carbon will exert a stronger attractive force on the second energy level electrons than the 5 protons of boron.
Increasing electron affinity from left to right across a period.
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