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Space Time & Motion A.2 Forces & Momentum (id: 94acb9092)

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admin 发表于 2024-2-9 18:41:07 | 显示全部楼层 |阅读模式
本题目来源于试卷: Space Time & Motion A.2 Forces & Momentum,类别为 IB物理学

[单选题]
A roller coaster loop has a radius Rypm,/t(no(3afxa (av(c-f5md 3x eya as shown in the diagram. The combined mass of a ca35yxd( mae-fcr and the passengers is M


When the car goes around the top of the loop, the normal reaction force of the track on the car is equal to half of the weight of the car and passengers.
Which expression gives the kinetic energy at the top of the loop?

A. 0
B. $\frac{RMg}{4}$
C. $\frac{3RMg}{4}$
D. RMg


参考答案:  C


本题详细解析:
At the top of the loop, the centripetal force is the vector sum of the combin/ct5 0w2u 9lp1knxnrned weight of the car and the passengers, and the 9nkwt1lncu/ r0p2xn5 normal force of the track on the car.

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