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Classification of Matter A.1 Periodic Table Elements Classification (id: f252243

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admin 发表于 2024-2-7 04:10:23 | 显示全部楼层 |阅读模式
本题目来源于试卷: Classification of Matter A.1 Periodic Table Elements Classification,类别为 IB化学

[问答题]
The table below contains data for the elements nitrogen, fluorin yy9zcyo5-bd.)+dbpc e, suocfu8 cmx ni9,6z2 x4b apmp+)lfur and chlorine in no particular order:fm)cp4n mxa6b 2+i8, 9pxczuo
Element is 1 ; Radius ($10^{−12}\,m$) is 71 ; First Ionization Energy ($kJ\,mol\,^{−1}$) is 1402.
Element is 2 ; Radius ($10^{−12}\,m$) is 104 ; First Ionization Energy ($kJ\,mol\,^{−1}$) is 1000.
Element is 3 ; Radius ($10^{−12}\,m$) is 100 ; First Ionization Energy ($kJ\,mol\,^{−1}$) is 1251.
Element is 4 ; Radius ($10^{−12}\,m$) is 60 ; First Ionization Energy ($kJ\,mol\,^{−1}$) is 1681.
1.Identify element 2 and justify your answer using the atomic radius and the first ionization energy data shown.
2.(1)Identify the number of valence electrons for element 1 and justify your answer using
the atomic radius and first ionization energy data shown.2
(2)State the electron configuration for the common ion formed from element 1.1
(3)Using section 9 (Section 10- 2025 Syllabus) in the data booklet, compare the size of the ionic radius of the common ion formed from element 1 to its atomic radius. Explain this change in size.2
3.An electron affinity for element 1 is not published and the electron affinity for element 4 is -328 $\,kJ\,mol^{−1}$. In terms of atomic structure, explain why element 1 does not have a value for electron affinity.




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