ΔH −136kJ mol$^{-1}$
ΔS −121JK$^{-1}$mol$^{-1}$
ΔG at 298K −99.9kJ mol$^{-1}$
1.1Explain why the enthalpy of formation of $H_2$ is 0kJmol$^{-1}$.
1.2Explain why the entropy change for this reaction is negative.
2.Explain how a reaction can be spontaneous with a negative entropy change.
3.Calculate the temperature at which this reaction is no longer spontaneous.
T= K
