What Drives Chemical Reactions D.2 Energy Cycles in Reactions (id: 1fc2789c8)

本题目来源于试卷: What Drives Chemical Reactions D.2 Energy Cycles in Reactions，类别为 IB化学

[单选题]
Sulfur dioxide ($SO_2$) reacts with oxygen and sulfuric acid($H_2SO_4$) to produce oleum($H_2S_2O_7$) in two reaction steps. The enthalpy cycle for this process is shown.

This process is used to produce a dilute solution of oleum in 5000g sulfuric acid from 0.80 mol sulfur dioxide. During the reaction, the temperature of the sulfuric acid increased by 22.8$^{\circ}C$.
What are the enthalpy changes of the second step,ΔH$_2$, and the overall process, ΔH$_total$, assuming no heat is lost during the reaction?
·Specific heat capacity of $H_2SO_4$,c=1.60Jg $^{-1}$K$^{-1}$;
·q=mcΔT.

A. Δ$H-2$(kJ mol$^{-1}$) is ΔH$_total$+99.0 ; ΔH$_total$(kJmol$^{-1}$) is $\frac{-(0.8×1000×1.60×22.8)}{5000}$
B. Δ$H-2$(kJ mol$^{-1}$) is ΔH$_total$+99.0 ; ΔH$_total$(kJmol$^{-1}$) is $\frac{-(5000×1.60×22.8)}{0.8×1000}$
C. Δ$H-2$(kJ mol$^{-1}$) is ΔH$_total$-99.0 ; ΔH$_total$(kJmol$^{-1}$) is $\frac{-(0.8×1000×1.60×22.8)}{5000}$
D. Δ$H-2$(kJ mol$^{-1}$) is ΔH$_total$-99.0 ; ΔH$_total$(kJmol$^{-1}$) is $\frac{-(5000×1.60×22.8)}{0.8×1000}$


参考答案:  B


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