How Much How Fast & How Far E.1 Amount of Chemical Change (id: 6f5436852)

本题目来源于试卷: How Much How Fast & How Far E.1 Amount of Chemical Change，类别为 IB化学

[单选题]

Nitrogen gas reacts with hydrogen gas to produce ammonia as per the following chemical equation:

$N_2$(g)+3$H_2$(g)→2$NH_3$(g)

If 0.86 molesmoles of$N_2$ are mixed with 0.50molesmoles of$H_2$, which reactant is in excess?

A. $N_2$
B. $H_2$
C. $NH_3$
D. Both reactants are in excess


参考答案:  A


本题详细解析:
A

(0.5mol$H_2$)($\frac{1molN_2} {3molH_2}$)=0.167mol$N_2$

Therefore, $0.5�����$ of $H_2$ require $0.167�����$ of$N_2$ to completely react. There are $0.86�����$ of $N_2$ available so $N_2$ is the reactant in excess$H$\mathrm{H}{\phantom{}}_2$

$H_2$$\mathrm{H}{\phantom{}}_2$

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