本题目来源于试卷: How Much How Fast & How Far E.1 Amount of Chemical Change，类别为 IB化学
[单选题]
Propane gas is combusted in oxygen gas according to the following equation:
$C_3H_8$(g)+5$O_2$(g)→3$CO_2$(g)+4$H_2O$(g)
When 11.0g of propane gas (MW 44.097) is combusted in 8.0g of oxygen gas, 0.20 moles of water vapor is produced.
What is the excess reactant and how many moles remain after the reaction is complete?
A. $O_2$,0.20moles
B. $C_3H_8$,0.20moles
C. $O_2$,0.25moles
D. $C_3H_8$,0.25moles
参考答案: B
本题详细解析:
B
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