[填空题]
The relationship between tx3d(vi:mp y8m p(+(qrq1k5lk o od:uxhe j(z9-jz d,*oc j /v*clh:spzz concentration of a reactant, A, and the time, for a second-order reactio/h9vj dz,j(zps oc* *zj:c-zln can be expressed using the equation below:
$\frac{1}{[A]}$=kt+$\frac{1}{[A]_0}$
Where [A] is the concentration of reactant A,[A] is the initial concentration of reactant $[A]_0$,t is the time in seconds,and k is a constant.
1.Calculate the gradient of the line and state the correct units.The number=
2.Use the graph to determine $[A]_0$(also known as the initial concentration of A).
$[A]_0$= mol dm$^{-3}$
3.Determine the time at which the concentration of A is equal to an eighth of its initial concentration.
[A]= mol m$^{-3}$
(If you were unable to complete parts (a), and (b), you may use k=0.02, and $[A]_0$ =42).
