本题目来源于试卷: How Much How Fast & How Far E.2 Rate of Chemical Change，类别为 IB化学
[单选题]
Sodium hydroxide and the ester ethyl acetate react with the rate equation:
$rate$=$\kappa$$[Ester][NaOH]$.
What are the units of the frequency factor, $A$, for this reaction? $\kappa$=$Ae^{-Ea/RT}$
A. $mol$ $dm^{-3}s^{-1}$
B. $mol^{-2}dm^{-3}s^{-1}$
C. $s^{-1}$
D. $mol^{-1}dm^{3}s^{-1}$
参考答案: D
本题详细解析:
D The rate constant and frequency factor have the same units. The reaction is second-order, so the units are $mol^{-1}dm^{3}s^{-1}$. $\kappa$=$\frac{mol dm^{-3}s^{-1}}{mol^{2}dm^{-6}}$
The question is at the higher end of the medium-difficulty category as students must be able to work out the units of a rate constant from a rate equation and also recognize that the units of the frequency factor are the same (or correctly interpret the given equation).
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