How Much How Fast & How Far E.2 Rate of Chemical Change (id: 997719bc7)

本题目来源于试卷: How Much How Fast & How Far E.2 Rate of Chemical Change，类别为 IB化学

[问答题]
The reactions of polluljf(.n ,ab(: kkhwf/ stants with ozone in the atmosphere is studied to i( q5 uvb1utkz8 (/g/xirhnd1b3p wv4 hnvestigate the effects on the hole in the ozone layer. One substance that rea58/u3vbdp hi kt1qx(w(nbrz 4gh/v1 ucts with ozone is nitrogen monoxide.
The reaction is: $O_3(g)$+$NO(g)$→$O_2(g)$+$N{O}_2(g)$

1.Use the data to determine the order of the reaction for each reactant, and the overall order of the reaction.

2.Give the rate expression for this reaction.Calculate$\kappa$for this reaction using a set of data from the table and determine its correct units.

3.What does the value of $\kappa$ suggest about this reaction in the atmosphere?

4.Suggest with a reason, a possible mechanism consistent with your rate expression.

​​In an experiment, the following data were collected at ${25}^{\circ }C$:

Trial	Concentration of $O_3$($mol$ $d{m}^{-3}$)	Concentration of $NO$($mol$ $d{m}^{-3}$)	Rate of reaction ($mol$ $d{m}^{-3}{s}^{-1}$)
1	$3.00\times {10}^{-3}$	$1.00\times {10}^{-3}$	$6.60\times 10$
2	$6.00\times {10}^{-3}$	$1.00\times {10}^{-3}$	$1.32\times {10}^2$
3	$9.00\times {10}^{-3}$	$1.00\times {10}^{-3}$	$1.98\times {10}^2$
4	$9.00\times {10}^{-3}$	$2.00\times {10}^{-3}$	$3.96\times {10}^2$
5	$9.00\times {10}^{-3}$	$3.00\times {10}^{-3}$	$5.94\times {10}^2$

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