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How Much How Fast & How Far E.2 Rate of Chemical Change (id: 997719bc7)

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admin 发表于 2024-2-6 23:36:29 | 显示全部楼层 |阅读模式
本题目来源于试卷: How Much How Fast & How Far E.2 Rate of Chemical Change,类别为 IB化学

[问答题]
The reactions of polv(t9m0na ;fyh ghay ;i w0wl*:lutants with ozone in ts(/fh5m mdbbp*fl5 y0ukv;/u2j lz( xhe atmosphere is studied to investigate the effects on the hole in d0 s5j/l*/vbkxff(p2u(l;yuzmb m5h the ozone layer. One substance that reacts with ozone is nitrogen monoxide.
The reaction is: $O_3(g)$+$NO(g)$→$O_2(g)$+$NO_2(g)$

1.Use the data to determine the order of the reaction for each reactant, and the overall order of the reaction.

2.Give the rate expression for this reaction.Calculate$\kappa$for this reaction using a set of data from the table and determine its correct units.

3.What does the value of $\kappa$ suggest about this reaction in the atmosphere?

4.Suggest with a reason, a possible mechanism consistent with your rate expression.

​​In an experiment, the following data were collected at $25^{\circ}C$:
Trial
Concentration of
$O_3$($mol$ $dm^{-3}$)
Concentration of
$NO$($mol$ $dm^{-3}$)
Rate of reaction
($mol$ $dm^{-3}s^{-1}$)
1
$3.00\times 10^{-3}$
$1.00\times 10^{-3}$
$6.60\times 10$
2
$6.00\times 10^{-3}$
$1.00\times 10^{-3}$
$1.32\times 10^{2}$
3
$9.00\times 10^{-3}$
$1.00\times 10^{-3}$
$1.98\times 10^{2}$
4
$9.00\times 10^{-3}$
$2.00\times 10^{-3}$
$3.96\times 10^{2}$
5
$9.00\times 10^{-3}$
$3.00\times 10^{-3}$
$5.94\times 10^{2}$





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