本题目来源于试卷: Mechanisms of Chemical Change F.2 Electron Transfer Reactions，类别为 IB化学
[单选题]
What is the balanced chemica jp;mr a n)3yvkv) d4yh6)cr.wl equay(hp0 4maq)bltion and $E^{\theta}$ cell for the spontaneous reaction between the following half-cells?
$Pb^{2+}(aq) + 2e^- \rightarrow Pb(s)$ -0.13V
$Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)$ +0.34V
A. Balanced Chemical Equation is $Pb^{2+}(aq) + Cu(s) \rightarrow Pb(s)+ Cu^{2+}(aq)$ $E^{\theta}$ is +0.47V
B. Balanced Chemical Equation is $Pb^{2+}(aq) + Cu(s) \rightarrow Pb(s)+ Cu^{2+}(aq)$ $E^{\theta}$ is +0.21V
C. Balanced Chemical Equation is $Cu^{2+}(aq) +Pb(s) \rightarrow Cu(s) + Pb^{2+}(aq)$ $E^{\theta}$ is +0.47V
D. Balanced Chemical Equation is $Cu^{2+}(aq) +Pb(s) \rightarrow Cu(s) + Pb^{2+}(aq)$ $E^{\theta}$ is +0.21V
参考答案: C
本题详细解析:
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