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How Much How Fast & How Far E.2 Rate of Chemical Change (id: 1d14f0f98)

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admin 发表于 2024-2-6 23:36:29 | 显示全部楼层 |阅读模式
本题目来源于试卷: How Much How Fast & How Far E.2 Rate of Chemical Change,类别为 IB化学

[单选题]
A reaction involvingguug. pg3e3: x ddb*6xpre4g3 l1tjf.3 ejjo/$X$ and $Y$ is measured and the following data is found:
Trial $[X]$$(mol dm^{-3})$ $[Y]$$(mol dm^{-3})$ $Rate$$(s^{-1})$
1 0.10 0.50 0.20
2 0.20 0.50 0.40
3 0.20 0.25 0.40

What possible mechanism is consistent with the data?

A. $X$+$X$→$I$(slow) $I$+$Y$→​$Z$ (fast)
B. $X$+$Y$→$I$(fast) $I$→​$Z$ (slow)
C. $X$→$I$(slow) $I$+$Y$→​$Z$ (fast)
D. $X$→$I$(fast) $I$+$Y$→​$Z$ (slow)


参考答案:  C


本题详细解析:
C
Using trials 1 and 2, as $[X]$ doubles, rate also doubles therefore first order with respect to $[X]$.
Using trials 2 and 3, as $[Y]$ halves, rate stays the same and so, zero order with respect to $[Y]$.
This gives a slow step that depends on unimolecular $X$, and not $Y$.

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