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Interaction & Interdependence C.1 Enzymes & Metabolism (id: 59e1e5985)

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admin 发表于 2024-2-7 00:13:17 | 显示全部楼层 |阅读模式
本题目来源于试卷: Interaction & Interdependence C.1 Enzymes & Metabolism,类别为 IB生物学

[单选题]
Which of the following besk+ -f nu)fwuw7t describes h;;l lwii8n77 jbtim)tl1c7.bh uqp 4the inhibitor in the image below?


A. Competitive inhibitor
B. Non-competitive inhibitor
C. End-product inhibitor
D. Cofactor


参考答案:  A


本题详细解析:
It is a competitive inhibitor because it binds to the active site which prevk /n6k6-zbw)knwc c ht,/eh /pents the substrate from binding. Non-competitive inhibitors (Choice B) do not bind to the active site. They bind at the allosteric site which alters the structure of the active site. This prevents the substrate from binding to the active site. End product inhibitors (Choice C) also regulate enzyme activity by binding at an allosteric site. A cofactor (Choice D) is usuall/w/pwtkzncb, k k6ne)-h ch /6y a non-protein molecule reversibly bound to the enzyme. Cofactors are not inhibitors and can be inorganic (e.g. zinc or iron).

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