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Interaction & Interdependence C.1 Enzymes & Metabolism (id: ddd180a44)

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admin 发表于 2024-2-7 00:13:17 | 显示全部楼层 |阅读模式
本题目来源于试卷: Interaction & Interdependence C.1 Enzymes & Metabolism,类别为 IB生物学

[单选题]
A metabolic pathway that conv8*2kak cik1e2/ lp wjv0vnfm(erts threonine to the end-pu z:1 -sn0dq5etcmn :nroduct isoleucine consists of five reactions. Threonine is converted to variousun esnd::1 cqzm-nt50 intermediate products sequentially by different enzymes before it is converted to isoleucine by the last enzyme in the pathway.
In the following diagram, the enzymes have been labelled as E1, E2, E3, E4 and E5.


Which of the following shows how this pathway is regulated?

A. Isoleucine inhibits E1, the enzyme that catalyses the first step of the pathway.
B. Isoleucine inhibits both E1 and E2, the enzymes that catalyse the first two steps.
C. Isoleucine inhibits E5, the enzyme that catalyses the last step.
D. Isoleucine inhibits all the enzymes in the pathway.


参考答案:  A


本题详细解析:
Isoleucine, the end product, inhibits E1 (threonine deh ;flhncey09p8 ydratase) by binding to the allosteric site of the enzyme. E1 catalyses the first reaction of the pathway. When there is an excess of the end-product isoleucine, it inhibits the first enzyme and prevents the buildup of intermediate products. Isoleucine inhibits E1 but not E2, so Choice B is incorrect. Isoleucilpf;h09c8 e nyne does not inhibit E5, so Choice C is incorrect. Isoleucine does not inhibit all the enzymes in the pathway, only E1. Choice D is therefore not correct.

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