本题目来源于试卷: Continuity and Change D.1 DNA Replication，类别为 IB生物学
[单选题]
The table below shows,+cs- 0c-jvnh(zxva63y rt gs the percentage of nitrogenous bases found in the Dqcta(hfo00.nko n5, - +iar jeNA of Escherichia coli bacrakn -oa0 h5coi( n0,q .+tfjeteria.
Adenine Cytosine Guanine Thymine
32% 18% 18% 32%
What conclusion can be made based on the data shown in the table above?
A. There is complementary base pairing between adenine and thymine, and between cytosine and guanine
B. The total amount of cytosine and guanine is less because there are fewer hydrogen bonds between cytosine and guanine
C. The bacteria contain a circular chromosome which prevents errors when nitrogenous bases pair up
D. The percentage composition of base pairs found in chromosomes and plasmids is different
参考答案: A
本题详细解析:
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