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Continuity and Change D.9 Homeostasis (id: 91f80f3e9)

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admin 发表于 2024-2-5 20:19:06 | 显示全部楼层 |阅读模式
本题目来源于试卷: Continuity and Change D.9 Homeostasis,类别为 IB生物学

[单选题]
Which row shows a correct diffi3 x/:8qsg (c*pzz npmez -2bwl6ejnv 0w-u9 narence in the blood concentration of various substan0nuwab2--z v ne96jlwces between the renal artery and renal vein?

A. Substance is Oxygen; Renal artery is Low; Renal vein High
B. Substance is Carbon dioxide; Renal artery is Low; Renal vein High
C. Substance is Glucose; Renal artery is High; Renal vein High
D. Substance is Urea; Renal artery is Low; Renal vein High


参考答案:  B


本题详细解析:

Choice B is correct because carbon dioxide concentration is higher in the renal vein due to aerobic respiration in the kidney.

Choice A is incorrect because oxygen concentration is higher in the renal artery; it is used by kidney cells for aerobic cellular respiration.

Choice C is incorrect because glucose concentration is lower in the renal vein as some of it is used for metabolic processes in kidney cells.

Choice D is incorrect because urea concentration is higher in the renal artery; urea is filtered out in the nephrons.

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