[填空题]
The equation of a liz7 o;hjmoh9s +e2pev: v 4++b7lspo-kn 0hgnone $L_1$ is 2x+3y=−5.
1.Find the gradient of $L_1$.
A second line, $L_2$, is perpendicular to $L_1$. $mL_1$ =
2.Find the gradient of $L_2$.
The point P(4,0)(4,0) lies on $L_2$. $mL_1$ =
3.Find the equation of $L_2$, giving your answer in the form ax+by+d=0, where a,b,d∈Z. a = b = d =
The point Q is the intersection of $L_1$ and $L_2$.
4.Find the coordinates of (a,b) a= b=
