[填空题]
A cannon-ball is fired from the top of a tower. The height,/pz;(5zyfyt :ex ze,t ℎh, in metres, oki lj)q(j. yb 6gm4xl)f the cannon-ball above the ground is modelled by the fun4jl)6x i(qbjk.ym l) gction
h(t)=−2$t^2$+20t+8,t≥0,where t is the time, in seconds, since the moment the cannon-ball was fired.
1.Write down the height of the tower. h = m
2.Calculate the height of the cannon-ball 5 seconds after it was fired.
The cannon-ball hits its target on the ground n seconds after it was fired. h = m
3.Find the value of n. n ≈
4.Find h′(t). h′(t) = at +b a = b =
5.Calculate the maximum height reached by the cannon-ball, and write down the corresponding time t.
6.Determine the total time the cannon ball was above the height of the tower. t = seconds