[填空题]
The volume V of a cube increases at az7k6 hhs;kv( a rate ofz2c9/v 5i 7sy,p5 zsqut-cdpz +y gzeb(7plx/ $4 \mathrm{~cm}^{3} \mathrm{sec}^{-1} $. Find the rate of change of the surface area of the cube, with respect to time t , at the instant when the volume of the cube is $8 \mathrm{~cm}^{3}$ .
the surface area is increasing at a rate of $\mathrm{~cm}^{2} / \mathrm{sec}$