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IB MAI HL Calculus Topic 5.2 Integration (id: 3d873a035)

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admin 发表于 2024-3-21 14:50:42 | 显示全部楼层 |阅读模式
本题目来源于试卷: IB MAI HL Calculus Topic 5.2 Integration,类别为 IB数学

[填空题]
The diagram below shows the cross-sectional areau e7s/,be z,kk(mvqc 5 jwc,0x of a mound of beach chl+02/e:)p vu a rbsisand created after a high tide.v2ru0/cei: slbp+) ha


The curve of the cross section can be modelled by the following equation

$y=\frac{x^{2}(90-x)}{1800}$

where y represents the vertical height of the mound in $\mathrm{cm}$ and x denotes the horizontal width in $\mathrm{cm}$ , from the start of the mound.
1. At a horizontal width of x=30 , determine
1. The vertical height of the mound at this point; y=   cm.
2. The gradient of the mound curve at this point. y'=$\frac{a}{b}$;a=  ,b=  .
2. 1. Find the value of x which corresponds to the maximum the vertical height of the mound;it is   .

2. Hence, find the maximum vertical height of the mound. y=   cm
3. Calculate the cross-sectional area of the mound, rounding your answer to one decimal place.

A child uses a toy shovel to remove the top of sand mound, as illustrated by the line segment $\mathrm{MN}$ below. Point M has coordinates at (30,30) .

4. Determine the coordinates of point N .

The cross-sectional area removed by the child can be expressed by the following integral

$\int_{p}^{q} \frac{x^{2}(90-x)}{1800} \mathrm{~d} x-R$,

5. Determine the values of p, q and R . p=  ; q=  , R=  .




参考答案:
空格1: 30空格2: 3空格3: 2空格4: 60空格5: 60空格6: 30空格7: 82空格8: 1560


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