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习题练习:SL/HL Topic C1.1 Enzymes and metabolism



 作者: admin   总分: 16分  得分: _____________

答题人: 匿名未登录  开始时间: 25年01月31日 10:44  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 1 题组 (共 4 题 4 分)
  1. How is reliability establp;hup0(0zv 3 ;zdws zu3xp9caished in an enzyme experiment?

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2#
 
单选题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
  2. What can cause anxhqycy/r y 5 )c832l8znlfs+ t enzyme to be denatured?

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3#
 
单选题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
  3. Which of the following correctly describe aspects of a metabolic pa83nzxa -0 :dy 7 qfxly-bx8zztthway?
I. It is regulated by one enzyme.
II. It is a series of reactions to produce an end product.
III. It is a system producing energy.
IV. It can be anabolic or catabolic in nature.

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4#
 
单选题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
  4. The binding of the substrate to the active site of an enw+/hg);g lynsuu4w-+ y c: holzyme causes which of the following nyhg lw)h/go yc:u;uw +-+ls4changes?
I. A change in the shape of the active site.
II. A change in the shape of the substrate.
III. A lowering of the activation energy of the reaction.
IV. The denaturation of the enzyme.

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5#
 
问答题 ( 1.0 分) (组内1/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第1/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
I. Explain why glucose is formed in the reaction hhi7vs1b9 t w/mixture.
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6#
 
问答题 ( 1.0 分) (组内2/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第2/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
II. List two variables thalwqdai yf, t)xj fdv(vk)1 )( s;xr,;gt should be controlled in this experiment, other than those g yatvj f)gl1 ,dw)(sr,;x (kfxi; dqv)iven.
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7#
 
问答题 ( 1.0 分) (组内3/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第3/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
III. Does the data collected indicate that the rate of the rea 6x,vlcygq6k.ction is constant in the firstcv.yxk6lg q,6 3 minutes?
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8#
 
问答题 ( 1.0 分) (组内4/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第4/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
IV. Calculate the rate of reaction in thic +dd/ozb;t6e first 5 minutes
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9#
 
问答题 ( 1.0 分) (组内5/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第5/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
V. Describe the changes islf.kps )), tr wbb5a2n the rate of reaction from the $4^{th}$ to the $8^{th}$ minute.
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10#
 
问答题 ( 1.0 分) (组内6/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第6/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VI. Why was it not necessary to collect dats;j78t ru3-w- g2sfev rcnaic+h9vr 9 hm;o4ba after the $8^{th}$ minute?
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11#
 
问答题 ( 1.0 分) (组内7/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第7/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VII. Predict, with a reason, the fructose concentration;* i 6 r)ugexfxwpwg5+arycvh3/x.y hjw53r* in the reaction mixture at th gax*c5 6hxv +j3w3girp/.)rhr fw5wexy ;*yue $6^{th}$ minute.
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12#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 3 题组 (共 1 题 1 分)
6. Enzymes are specific to)lz rs6y4lo( 8kwqv(v a particular reaction. Explain why enzyme specificity is important in the con8lov6 lw( k4yrq()s vztrol of metabolic pathways.
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13#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
I. Penicillin does na21a almi((fo7qo 9nz ot affect human enzymes.
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14#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
II. Penicillin is a permanent compec0f0)f ga o9nutitive inhibitor of transpeptidase.
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15#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
III. Suggest how penicillin resistance has developed in som5ck( 88 o,rbrgnsnyxz. l ht9(e bacteria.
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16#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
8. ATP is an allosteric inhib:upoauuq yq3w:*o8b /nq6 z9vp7y *rxitor of phosphofructokinase and pyruvate kinase, two enzymes involve 3uu/nxb rq*p9qo:vuz:p wy86 7yqoa*d in glycolysis. Discuss the importance of feedback inhibition of metabolic pathways in biological systems using this as an example.
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