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习题练习:SL/HL Topic C1.1 Enzymes and metabolism



 作者: admin   总分: 16分  得分: _____________

答题人: 匿名未登录  开始时间: 25年01月31日 10:44  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 1 题组 (共 4 题 4 分)
  1. How is reliability established in an enzymlx jrp::jzd;5 e experiment?

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2#
 
单选题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
  2. What can cause an enzyme to be 4 uir.4.c7hkb tj4bka denatured?

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3#
 
单选题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
  3. Which of the following correctly describe aspects of a metabolic p p ;-wekq0yj hrof7/2wop;u(o athway?
I. It is regulated by one enzyme.
II. It is a series of reactions to produce an end product.
III. It is a system producing energy.
IV. It can be anabolic or catabolic in nature.

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4#
 
单选题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
  4. The binding of the substrate to the active site of an enzymz:r0w) z 7fzlne causes which of the following cha:)0 wf 7nlrzzznges?
I. A change in the shape of the active site.
II. A change in the shape of the substrate.
III. A lowering of the activation energy of the reaction.
IV. The denaturation of the enzyme.

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5#
 
问答题 ( 1.0 分) (组内1/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第1/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
I. Explain why glucose is formed inm0 hq6hs) -vs9rr gu movn.6y0 the reaction mixture.
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6#
 
问答题 ( 1.0 分) (组内2/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第2/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
II. List two variables that should be controlled in this experimentivo wgw 5yvf8l1lyp4wa- (n),, other than th(vnw -l) w5yfopwa4lg8,i v1yose given.
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7#
 
问答题 ( 1.0 分) (组内3/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第3/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
III. Does the data collected indicate that the rate of the reaction is cop ; -tqp05v1remgg+b ( ,glbzonstant in the first 3 minutespv 5ogqegrpz1+0t,gb;(l-bm ?
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8#
 
问答题 ( 1.0 分) (组内4/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第4/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
IV. Calculate the rate of reaction in (i0s9yd4nhz,(0ufz p o9i6 bgtl t;4jwx5sio the first 5 minutes
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9#
 
问答题 ( 1.0 分) (组内5/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第5/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
V. Describe the changes in the rate of reaction fr(hso v3;zqth i k vsz;j5 v079s*yw5brom the $4^{th}$ to the $8^{th}$ minute.
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10#
 
问答题 ( 1.0 分) (组内6/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第6/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VI. Why was it not necessary to collect data aftkq6us)u c7x3/ 3 *rw puv*yxkder the $8^{th}$ minute?
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11#
 
问答题 ( 1.0 分) (组内7/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第7/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VII. Predict, with a reasonqn;mz b.2i t1l, the fructose concentration in the reaction mixture at t2b;m iqz.1ln the $6^{th}$ minute.
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12#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 3 题组 (共 1 题 1 分)
6. Enzymes are specific to a particular reactioe.1 sek8d .2vswnw;n y;ezqm;n. Explain why enzyme specificity is important in thnw ;s.vq8e1md;;ezwnksy. e2e control of metabolic pathways.
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13#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
I. Penicillin does not aff*j5s4 ra,zexj,;nf rrect human enzymes.
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14#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
II. Penicillin is a permanent competitive inhibitor of transpeptnl: rwh/cf 0mw69yo4m42jxpu idase.
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15#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
III. Suggest how penicillin resistance has developedwby0ywxah6fi(h4g0 x11p ( hh in some bacteria.
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16#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
8. ATP is an allosteric inhibitor of phosphofructokinase and pyruvate k4 edkhl*c8u-binase, two enzymes involved in glycolysis. Discuss the importance of feedbacu-e 8kl4*hbdc k inhibition of metabolic pathways in biological systems using this as an example.
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