题库网 (tiku.one)

 找回密码
 立即注册

 

      

上传图片附件

未使用图片

小贴士: 允许的图片文件格式为: gif, jpg, jpeg, png, webp，上传完成后会在上方生成预览，用鼠标连续双击缩略图，或拖动缩略图，该图片就被绑定至本题，显示在题目下方

本次作答已使用

小贴士: 此栏目显示的是当前作答使用的所有图片，绑定到某一题目的图片同时会显示在该题目下方; 删除使用的图片会将其转移到<未使用图片>类别


习题练习：SL/HL Topic D3.2 Inheritance
本习题练习来源于题库网 (https://tiku.one)，是在线习题练习的打印版，您也可以访问本平台网站(https://tiku.one/)直接在线完成(注册并登录账号后在首页左侧输入试卷号 591 即可在线作答)，，作答电子化后可随时回放，查看每题答案与详细解析，搜藏保存任意题目；教师使用本平台可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力。本试卷的直接作答链接 https://tiku.one/test591.html
 作者: admin  发布日期: 2025-02-01 15:03    总分: 15分  得分: _____________

答题人: 匿名未登录  开始时间: 02月01日 01:21  切换到: 整卷模式

标记此题
1#
 
单选题 ( 1.0 分) (组内1/5) 切至整卷模式 搜藏此题  
第 1 题组 (共 5 题 5 分)
  1. Red-green colour blindness is caused by an X-linked recessivepx dor(l-l e xf9a8d3/74ljl r allele. In the pedigree chart below which individuals must be carriers of the red-green colourp/ adfl 7 jrlxl-r8(doxl9 e34 blindness allele?


参考答案:    
标记此题
2#
 
单选题 ( 1.0 分) (组内2/5) 切至整卷模式 搜藏此题  
  2. If the parents in the ped mka1mkf-4tp z9 (a2oqigree chart above had a fourth child who was female, what wo(a 42k zfm1toa qkpm-9uld be the probability that she was colour blind?

参考答案:    
本习题练习全部题目来源于题库网 (https://tiku.one)，学生可自助刷题练习，扫右侧二维码加微信，获取学习资料，答疑辅导
教师可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力
标记此题
3#
 
单选题 ( 1.0 分) (组内3/5) 切至整卷模式 搜藏此题  
  3. In Labrador dogs, black coa:0.* k i m-q/gcru2 nz-8ximzizj8x bpt is dominant over chocolate coat. The genotype ofmmiz-: * xgipknj 8 8-bizuqx0cz/.2 r a black male labrador is unknown. How can the genotype of this black Labrador be determined?

参考答案:    
本习题练习全部题目来源于题库网 (https://tiku.one)，学生可自助刷题练习，扫右侧二维码加微信，获取学习资料，答疑辅导
教师可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力
标记此题
4#
 
单选题 ( 1.0 分) (组内4/5) 切至整卷模式 搜藏此题  
  4. Which of the following 1p c (gvfm+2ox*rn1knzub kp1. mex+ *best defines the term, “gene”?

参考答案:    
标记此题
5#
 
单选题 ( 1.0 分) (组内5/5) 切至整卷模式 搜藏此题  
  5. Phenylketonuria (PKU) is an inhexd5 .rro8c-)ywx5df crited human disease caused by a recessive autosomal ady5. wfxrc5o x c-8r)dllele in a gene which codes for an enzyme needed to convert phenylalanine to tyrosine. The PKU allele produces a non-functional enzyme.
Which of the following statements are correct?
I. Two parents heterozygous for the condition could have a child with PKU.
II. If the mother of the child is homozygous and not affected by PKU, her children will not be affected.
III. The polypeptide sequence of the enzyme of an affected person is identical to a person without the condition.
IV. Two parents who are not affected with PKU cannot have a child with the disorder.

参考答案:    
标记此题
6#
 
问答题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第1/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
I. Identify which of the alleles, yellow or green, is domin4pk8wmx3kldpua;ofz8 3x r6 2ant.
参考答案:    
本习题练习全部题目来源于题库网 (https://tiku.one)，学生可自助刷题练习，扫右侧二维码加微信，获取学习资料，答疑辅导
教师可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力
标记此题
7#
 
问答题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第2/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
ii. Deduce the genotypsq; 1yaq w,l9alm ac1r 5q3fw-e of the offspring.
参考答案:    

标记此题
8#
 
问答题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第3/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iii. Construct a Punnet grid to d0f2bmo;e :gex x+k n.nx*l d9show the cross between two offspring plants of tbn92;fn eod:xmd 0x.* kxe l+ghe F1 generation.
参考答案:    

标记此题
9#
 
问答题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第4/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iv. Deduce the phenotypic ratio for the offk /sk q.t9gbq,.* *qvxpksa,y spring of the F1 cross.
参考答案:    
本习题练习全部题目来源于题库网 (https://tiku.one)，学生可自助刷题练习，扫右侧二维码加微信，获取学习资料，答疑辅导
教师可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力
标记此题
10#
 
问答题 ( 1.0 分) (组内1/2) 切至整卷模式 搜藏此题  
第 3 题组 (共 2 题 2 分)
7. Amand has a daughter with Padmavathi.eyd w-2 8yfrvuhx-(d, Amand is blood group A, Padmavathi is blood group B, and their daughter is blood group O. They are having a second child, yvw28-, d(fhd-xrueya son.
Deduce the probability that their unborn son will be blood group O. Explain your working.
参考答案:    

标记此题
11#
 
问答题 ( 1.0 分) (组内2/2) 切至整卷模式 搜藏此题  
8. Explain how inher1o8qcut8)gedbh x j3d4ph i 4ab dvfn+(++yt2itance and environmental factors can interact in a phenotype to cause the appearance of human skui+ d 2(xd1 h3+tfedcab 4j h4o8+gq8)tnyp bvin colour.
参考答案:    

标记此题
12#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题 
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
a. Deduce genotypes for the three coat colour phenotypes in t/ov +/, yg lcv7. jn-g.auydokhese cattle.
Use the symbols $C^W$ for the white coat allele, and $C^R$for red coat allele.
参考答案:    
本习题练习全部题目来源于题库网 (https://tiku.one)，学生可自助刷题练习，扫右侧二维码加微信，获取学习资料，答疑辅导
教师可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力
标记此题
13#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题 
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
b. Deduce the parental genotypen7;nunf(31 r2ux ount s of the cow in the image.
Use P for the allele for polled and p for the allele for horns.
参考答案:    
本习题练习全部题目来源于题库网 (https://tiku.one)，学生可自助刷题练习，扫右侧二维码加微信，获取学习资料，答疑辅导
教师可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力
标记此题
14#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题 
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
c. The roan colour, poz*1,m8 hry-ov2 ndnyyzcy10z lled cow in the image is mated with a white coat, horned bull. yyz-y o1 mnz2*zhcv1r 80n,dy
Construct a Punnett square showing all possible phenotypes of the offspring.
参考答案:    

标记此题
15#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
10. The pedigree chart shows ABO bloodf)xchibqo tqu )+mgmc i00 ib6212(bl group alleles and their genotype for nail-patella syndrome, an inherited ct 6mocm1 2l 2u hi bqcxi+0b(giq0)b)fondition. The individuals 1, 3, and 4 in row III are recombinants. Image by D.B. Pylypiv.

Use the pedigree chart to explain the meaning of gene linkage.
参考答案:    

  • :
    •
    总分:15分 及格:9分 时间:不限时
    未答题: 已答题:0 答错题:
    当前第 题，此次习题练习共有 15 道题
    本系统支持习题练习，作业与考试三大模式，作业考试自动评分，成绩排序一键导出，可设定动态变量同一试卷千人千题
    如果您对本系统感兴趣，想加入我们或者想进行任何形式的合作，请加微信 skysky1258

    试卷内容到此结束!   © 2024 题库网 (https://tiku.one)版权所有

    浏览记录|使用帮助|手机版|切到手机版|题库网 (https://tiku.one)

    GMT+8, 2025-2-23 06:31 , Processed in 0.108034 second(s), 63 queries , Redis On.