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习题练习：SL/HL Topic D3.2 Inheritance
本习题练习来源于题库网 (https://tiku.one)，是在线习题练习的打印版，您也可以访问本平台网站(https://tiku.one/)直接在线完成(注册并登录账号后在首页左侧输入试卷号 591 即可在线作答)，，作答电子化后可随时回放，查看每题答案与详细解析，搜藏保存任意题目；教师使用本平台可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力。本试卷的直接作答链接 https://tiku.one/test591.html
 作者: admin  发布日期: 2025-02-01 15:03    总分: 15分  得分: _____________

答题人: 匿名未登录  开始时间: 02月01日 01:21  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) (组内1/5) 切至整卷模式 搜藏此题  
第 1 题组 (共 5 题 5 分)
  1. Red-green colour blindness is caused by an X-linked r9lv xn/ 5t*tin+n.c4yir fw-recessive allele. In the pedigree chart below which individuals muil5 xn9 inf.v- ytrc+n4 /rw*tst be carriers of the red-green colour blindness allele?


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2#
 
单选题 ( 1.0 分) (组内2/5) 切至整卷模式 搜藏此题  
  2. If the parents in th:dr5 6pp opt7jz9(fmu e pedigree chart above had a fourth child who was female, what would be the j ztp(p5 7:mfd orp96uprobability that she was colour blind?

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3#
 
单选题 ( 1.0 分) (组内3/5) 切至整卷模式 搜藏此题  
  3. In Labrador dogs, black coat is dominant over chocolateo vk *-nvsk du7/f-3fwml7h6 w coat. The genotype of a black male labrador is unknown. How can t6wf u w lv*7 sd--/vk37omfnkhhe genotype of this black Labrador be determined?

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4#
 
单选题 ( 1.0 分) (组内4/5) 切至整卷模式 搜藏此题  
  4. Which of the following best defines the term, jvnx j o30y)sau4vy--“gene”?

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5#
 
单选题 ( 1.0 分) (组内5/5) 切至整卷模式 搜藏此题  
  5. Phenylketonuria (PKU) is an inherited human c ,4 abf8l;h 6 lfnjmlvmr 0tj+*na/2bdisease caused by a recessive autosomal allele in a gene which codes for an enzf 4latnhb*8;a,br6nl 2v m/m0cj+ j lfyme needed to convert phenylalanine to tyrosine. The PKU allele produces a non-functional enzyme.
Which of the following statements are correct?
I. Two parents heterozygous for the condition could have a child with PKU.
II. If the mother of the child is homozygous and not affected by PKU, her children will not be affected.
III. The polypeptide sequence of the enzyme of an affected person is identical to a person without the condition.
IV. Two parents who are not affected with PKU cannot have a child with the disorder.

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6#
 
问答题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第1/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
I. Identify which of the alleln puz9 q4t,4w8n-e,f4xjrtvsn-pve 8es, yellow or green, is dominant.
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7#
 
问答题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第2/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
ii. Deduce the genotylmsq8 oi l/w2s i97sv9p b2d6lpe of the offspring.
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8#
 
问答题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第3/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iii. Construct a Punnet grid to show n*urh0qk 7czy*fr5meq;gawp 260j , dthe cross between two offspring plants of the F1 generatiou*zmq6h 0; * ,da0jrwkf 27qgecypn 5rn.
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9#
 
问答题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第4/4题 
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iv. Deduce the phenotypic ratio for thepel6-itkp24 ts*lra1r / ;dhh offspring of the F1 cross.
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10#
 
问答题 ( 1.0 分) (组内1/2) 切至整卷模式 搜藏此题  
第 3 题组 (共 2 题 2 分)
7. Amand has a daughter with Padmavathi. Amand i kj6nmratt-k2.t0aa: *rl2fds blood group A, Padmavathi is blood group B, and their daughter is blood g6:ntk*a0 ardmtjfa 2klr-2t .roup O. They are having a second child, a son.
Deduce the probability that their unborn son will be blood group O. Explain your working.
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11#
 
问答题 ( 1.0 分) (组内2/2) 切至整卷模式 搜藏此题  
8. Explain how inheritance and environmental factc5+ac9 ;ostzu ors can interact in a phenotype to cause the ;uzo cc+95tas appearance of human skin colour.
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12#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题 
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
a. Deduce genotypes for the three coat colour phezvw.e qh8:j4 hnotypes in these cattle.
Use the symbols $C^W$ for the white coat allele, and $C^R$for red coat allele.
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13#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题 
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
b. Deduce the parental g r9u/z m-vqp:jenotypes of the cow in the image.
Use P for the allele for polled and p for the allele for horns.
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14#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题 
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
c. The roan colour, bu67+n2 4mfrz )f atzxf;v:l rpolled cow in the image is mated with a white coat, horned bull. t7x; lzbmufr4+)r f va:z n2f6
Construct a Punnett square showing all possible phenotypes of the offspring.
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15#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
10. The pedigree chart shows An35 kj,8x-k8wms +5h2bbzd3wekuo dzBO blood group alleles and their genotype for nail-patella syndrome, an inherited condition. The individ3hukzo3 5+zs8 nw w 2jemx5-,8bbkkdduals 1, 3, and 4 in row III are recombinants. Image by D.B. Pylypiv.

Use the pedigree chart to explain the meaning of gene linkage.
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