题库网 (tiku.one)

 找回密码
 立即注册

 

      

上传图片附件

未使用图片

小贴士: 允许的图片文件格式为: gif, jpg, jpeg, png, webp,上传完成后会在上方生成预览,用鼠标连续双击缩略图,或拖动缩略图,该图片就被绑定至本题,显示在题目下方

本次作答已使用

小贴士: 此栏目显示的是当前作答使用的所有图片,绑定到某一题目的图片同时会显示在该题目下方; 删除使用的图片会将其转移到<未使用图片>类别


习题练习:SL/HL Topic D3.2 Inheritance



 作者: admin发布日期: 2025-02-01 15:03   总分: 15分  得分: _____________

答题人: 匿名未登录  开始时间: 25年02月01日 01:21  切换到: 整卷模式

标记此题
1#
 
单选题 ( 1.0 分) (组内1/5) 切至整卷模式 搜藏此题  
第 1 题组 (共 5 题 5 分)
  1. Red-green colour blindness is caused by an X-linked recessive allele. Iq75edu ldwhgm5a85i f:ht1y, n the pedigree chart below which individuals must be carriers of the red-green colour bl 8 t5qald7 f5u ye,mhh5d:gw1iindness allele?


参考答案:    

标记此题
2#
 
单选题 ( 1.0 分) (组内2/5) 切至整卷模式 搜藏此题  
  2. If the parents in the pedigree chart above had a fourth child who :fvj+axeu- cgbn 45 2rwas female, what would beg jnuvebr2x45 c+-af: the probability that she was colour blind?

参考答案:    

标记此题
3#
 
单选题 ( 1.0 分) (组内3/5) 切至整卷模式 搜藏此题  
  3. In Labrador dogs, black coat is w/uz941a uim91ce gcn dominant over chocolate coat. The genotype of a black male labrador is unknown. Hu9w9/uz1c4nma1ci g eow can the genotype of this black Labrador be determined?

参考答案:    

标记此题
4#
 
单选题 ( 1.0 分) (组内4/5) 切至整卷模式 搜藏此题  
  4. Which of the following best defines the term, “genef8t9p ch rc,7g”?

参考答案:    

标记此题
5#
 
单选题 ( 1.0 分) (组内5/5) 切至整卷模式 搜藏此题  
  5. Phenylketonuria (PKU) is an inherited human dicw 5c)do,8nrd2. nfd wsease caused by a recessive autosomal n ) wf,8cd.5w2dr cdnoallele in a gene which codes for an enzyme needed to convert phenylalanine to tyrosine. The PKU allele produces a non-functional enzyme.
Which of the following statements are correct?
I. Two parents heterozygous for the condition could have a child with PKU.
II. If the mother of the child is homozygous and not affected by PKU, her children will not be affected.
III. The polypeptide sequence of the enzyme of an affected person is identical to a person without the condition.
IV. Two parents who are not affected with PKU cannot have a child with the disorder.

参考答案:    

标记此题
6#
 
问答题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第1/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
I. Identify which of the alleles, yellow or 8oqqnyp;1rs.cj 79qggreen, is dominant.
参考答案:    

标记此题
7#
 
问答题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第2/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
ii. Deduce the genotype of the (4(wbvtw7 xu:dbk d:soffspring.
参考答案:    

标记此题
8#
 
问答题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第3/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iii. Construct a Punnet grid to show the cross between two offsprii8lk/gkwuz4h2jdesx /d+ z , 7ng plants of the F1+gz/72zdw /8x,uks k4hd jiel generation.
参考答案:    

标记此题
9#
 
问答题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
第 2 题组 (共 4 题 4 分) 当前第4/4题
题组内容描述:
6. In a genetic cross by Gregor Mendel, pure breeding pea plants with yellow seeds were crossed with pure breeding plants with green seeds. All the offspring, F1 generation, had yellow seeds.
Iv. Deduce the phenotypic ratio for the offspring of the F1 cf(2;sw+ss:bnll zeat* 7 v v7pross.
参考答案:    

标记此题
10#
 
问答题 ( 1.0 分) (组内1/2) 切至整卷模式 搜藏此题  
第 3 题组 (共 2 题 2 分)
7. Amand has a daughter with Padmavathi. Amand is blood group A, Pafonz8:axqth 3/(d3hc dmavathi is blood group B, and thx( ohzfd83:q3 hnta/ceir daughter is blood group O. They are having a second child, a son.
Deduce the probability that their unborn son will be blood group O. Explain your working.
参考答案:    

标记此题
11#
 
问答题 ( 1.0 分) (组内2/2) 切至整卷模式 搜藏此题  
8. Explain how inherita,py* uz,7sbli nce and environmental factors can interact in a phenotype to cause the appea *7up,z ly,bisrance of human skin colour.
参考答案:    

标记此题
12#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
a. Deduce genotypes for the e0q-bdobo / ux*v*de(three coat colour phenotypes in these cattle.
Use the symbols $C^W$ for the white coat allele, and $C^R$for red coat allele.
参考答案:    

标记此题
13#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
b. Deduce the parental genotypes of the cow in the imag8cphckz+ kl97guzh f*wh2)p , e.
Use P for the allele for polled and p for the allele for horns.
参考答案:    

标记此题
14#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题
题组内容描述:
9. The breed of cow shown in the image can have white, red or roan coat colour. They can also have horns or be polled (without horns). The image shows a polled cow with roan coat colour. This cow is the product of a mating between a pure breeding bull, with a red coat and no horns and a pure breeding cow with a white coat and horns.
c. The roan colour, polled cow in the image is-j nl u9siw7*r mated with a white coat, horned bul7luwr ij9*-sn l.
Construct a Punnett square showing all possible phenotypes of the offspring.
参考答案:    

标记此题
15#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
10. The pedigree chart shows 1jqhpb3):o s96yf xfucx:vjp. 7t+ ag ABO blood group alleles and their genotype for nail-patella syndrome, an inherited condition. The individuals 1, 3, and 4 in row p p9 u)1y3t qsaxvh j+g:6fx.b7oj:fcIII are recombinants. Image by D.B. Pylypiv.

Use the pedigree chart to explain the meaning of gene linkage.
参考答案:    

  • :
  • 总分:15分 及格:9分 时间:不限时
    未答题: 已答题:0 答错题:
    当前第 题,此次习题练习共有 15 道题
    本系统支持习题练习,作业与考试三大模式,作业考试自动评分,成绩排序一键导出,可设定动态变量同一试卷千人千题
    如果您对本系统感兴趣,想加入我们或者想进行任何形式的合作,请加微信 skysky1258

    浏览记录|使用帮助|手机版|切到手机版|题库网 (https://tiku.one)

    GMT+8, 2025-4-25 16:40 , Processed in 0.104464 second(s), 64 queries , Redis On.