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习题练习:IB MAI HL Number and Algebra Topic 1.2 Sequences & Series



 作者: admin   总分: 47分  得分: _____________

答题人: 匿名未登录  开始时间: 24年01月19日 19:49  切换到: 整卷模式

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1#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Only one of the following four sequences is arithmetic +2k a x4ulha7reiwk0.and only one of them is geo+xk h4l20au. 7wakire metric.


1.State which sequence is arithmetic and find the common difference of the sequence.
Hence Cn is arithmetic and d=  .
2.State which sequence is geometric and find the common ratio of the sequence.
Hence dn is geometric and r=  .
3.For the geometric sequence find the exact value of the eighth term. Give your answer as a fraction.
Using the nth term formula dn .

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2#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Only one of the following four sequences is arithmetic and only one of them is ok w,q9u5ht erhi*cj2sk7(w(gcqs(,9 kw h*2ir we57tk oj(hueometric.

1.State which sequence is arithmetic and find the common difference of the sequence.
Hence bn is arithmetic and d=  .
2.State which sequence is geometric and find the common ratio of the sequence.
Hence Cn is geometric and r=  .
3.For the geometric sequence find the exact value of the sixth term. Give your answer as a fraction.

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3#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  An arithmetic sequence honz vim,t5 9ox:7fp c(g pr--kas u1=40,u2=30,u3=24

1.Find the common difference, d.
The common difference is d=-  .
2.Find u8.
​Using the nth term formula un=-  .
3.Find S8.
S8 .

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4#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  An arithmetic sequence b,pxa4ar /++3sya f,lhz ag-u has u1=12, u2=21, u3=30.
1.Find the common difference, d.
d=  .
2.Find u10.
u10 .
3.Find S10.
S10 .

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5#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The 15th term of an arithmetic sequence is 2 ;pj fx km)d;51wsb,wim5,mxm1 and the common difference is −4.

Find the first term of the sequence.
u1 .
Find the 29th term of the sequence.
u29=-  .
Find the sum of the first 40 terms of the sequence.
S40=-  .

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6#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A geometric sequence ysjky 6)yo9yc kp 22e7has u1=5, u2=-1 and u3=15.
Find the common ratio, r.
r=1x,那么x =   .
Find the exact value of u7.
u7=1x,那么x =   .
Find the exact value of S7.
S7=13021x,那么x =   .

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7#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A tennis ball bounces on the ground n times. The hx2cchi wj.84buf+- dheights of the bounces, ​h1,h2,h3,....,hn, form a geometric sequence. The height that the ball bounces the first time, h1, is 80 cm, and the second time, h2 , is 60 cm.

Find the value of the common ratio for the sequence.
r=  .
Find the height that the ball bounces the tenth time, 10​ .
10​=  .
Find the total distance travelled by the ball during the first six bounces (up and down). Give your answer correct to 2 decimal places.
The number=  cm

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8#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A geometric sequence has 20 terms, with the first four terms given belx1 .uwfu hu.x/wzmf3) ow.

418.5,279,186,124,…


1.Find r, the common ratio of the sequence. Give your answer as a fraction.
r=2x 那么x =   
2.​Find u5, the fifth term of the sequence. Give your answer as a fraction.
u5=x3 那么x =   
3.Find the smallest term in the sequence that is an integer.
u4 .
4.Find S10 , the sum of the first 10 terms of the sequence. Give your answer correct to one decimal place.
S10 .

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9#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Emily starts reading Leo Tolstoy's War and Peace on the 1st ( uso4tof lp1:of February. The number of pages she reads each day increases by l:p uo41ot s(fthe same number on each successive day.

1.Calculate the number of pages Emily reads on the 14th of February.
u14 pages
2.Find the exact total number of pages Emily reads in the 28 days of February.
S28 pages

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10#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The table shows the first four terms of three se/nm4tz0j( v21 n(fmz.fx l jhdquences: un , vn , and wn.

1.State which sequence is
1.1.arithmetic is   ;

1.2.geometric is   .

2.Find the sum of the first 50 terms of the arithmetic sequence.
S50 .
3.Find the exact value of the 13th term of the geometric sequence

W13 .

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11#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The table below shows the first four terms of n7-o xd.r0u-o: x nob56scpsw three sequences: un,vn,wn.


1.State which sequence is

1.1.arithmetic is   ;

1.2.geometric is   .

2.Find the exact value of the sum of the first 35 terms of the arithmetic sequence.
S35 .
3.Find the exact value of the 10th term of the geometric sequence.
w10 .

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12#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The third term, u3 , of an arithmetic sequence is 7. The common difference of
the sequence, d, is 3.
Find u1 , the first term of the sequence.
u1 .
Find u60 , the 60th term of sequence.
u60 .
The first and fourth terms of this arithmetic sequence are the first two terms
of a geometric sequence.

Calculate the sixth term of the geometric sequence.
u6 .

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13#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The fifth term, u5 , of a geometric sequence is 125. The sixth term, u6 , is 156.25.

Find the common ratio of the sequence.
r=  .
Find u1 , the first term of the sequence.
u1 .
Calculate the sum of the first 12 terms of the sequence.
S12 .

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14#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The fourth term, u4 , of a geometric sequence is 135. The sixth term, u5 , is 81.

Find the common ratio of the sequence.
r=  .
Find u1 , the first term of the sequence.
u1 .
Calculate the sum of the first 20 terms of the sequence.
S20 .

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15#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The fifth term, u5 , of a geometric sequence is 25. The eleventh term, u11 , of the same sequence is 49.

Find d, the common difference of the sequence.
d=  .
Find u1 , the first term of the sequence.
u1 .
Find S100 ,the sum of the first 100 terms of the sequence.
S100 .

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16#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The fifth term, u5 , of a geometric sequence is 5. The eleventh term, u8 , of the same sequence is 14.

Find d, the common difference of the sequence.
d=  .
Find u1 , the first term of the sequence.
u1=-  .
Find S100 ,the sum of the first 100 terms of the sequence.
S100 .

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17#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  On the first day of September, 2019, Gloria planted 5 flowers in h1q6cbt:cagm l kj (;z0x b0*rser garden. The number of flowers, which she plants at every day of the month, forms an arithmetic sequence. The number ob0:(b 0grc6;aczltkq 1*s xmjf flowers she is going to plant in the last day of September is 63.

1.Find the common difference of the sequence.
d=  .
2.Find the total number of flowers Gloria is going to plant during September.
S30 .
3.Gloria estimated she would plant 1000 flowers in the month of September. Calculate the percentage error in Gloria's estimate.
ϵ=  %

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18#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The fifth term, u5 , of geometric sequence is 375. The sixth term, u6,of the sequence is 75.
1.Write down the common ratio of the sequence.
r=  .
2.Find u1.
u1 .
The sum of the first k terms in the sequence is 292968.

3.Find the value of k.
k=  .

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19#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  In this question give alle9atqr8p (a)c p0b,u l answers correct to the nearest whole number.

A population of goats on an island starts at 232. The population is expected
to increase by 15 % each year.

1.Find the expected population size after:
1.1. 10 years;
u10 
1.2. 20 years..
u20 
Find the number of years it will take for the population to reach 15000.
n≈  .

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20#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A 3D printer builds a set of 49 Eiffel Tower Replicas in difft4q h2--uluqy:vybm 1o d gn(8erent sizes. The height of the largest tower in this set is 64 cm. The heights of successive smaller towers are 95 % of the preceding larger tower, as shown in the diagram below.lg:tbn 4dy-h8 -qm1vu qu2yo(

1.Find the height of the smallest tower in this set.
u49 .
2.Find the total height if all 49 towers were placed one on top of another.
S49 .

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21#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The second and the third terms of a gev:8 n qqor8ylkov0jk kf4c4/.ometric sequence are u2=3 and u3=6.

1.Find the value of r, the common ratio of the sequence.
r=  .
2.Find the value of u6.
u6 .
3.Find the largest value of n for which un is less than 104.
n=  .

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22#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The Australian Koala Foundatwm8zreh;*dwj( m;hq z2o1a d6ion estimates that there are about 45000 koalas left in the wild in 2019. A year (d h6maqdozr; 8*wwe j;2mhz1 before, in 2018, the population of koalas was estimated as 50000. Assuming the population of koalas continues to decrease by the same percentage each year, find:

1.the exact population of koalas in 2022;
2022:=  .
2.the number of years it will take for the koala population to reduce to half of its number in 2018.

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23#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The sum of the first n terms of an arithmetic sequence, jl*/ vi;eto8a/p j9jz Sn=u1+u2+u3+...+un,is given by Sn=2n2+n.

1.Write down the values of S1 and S2.
S1  ; S2 .
2.Write down the values of u1 and u2.
u1  ; u2 .
3.Find d, the common difference of the sequence.
d=  .
4.Find u10​ , the tenth term of the sequence.
u10 .
5.Find the greatest value of n, for which ​un is less than 100.
n=  .
6.Find the value of n, for which Sn is equal to 1275.
n=  .

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24#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A battalion is arranged, per row, aclt p-wnhcj+i fkqmmr1 9:(n :+cording to an arithmetic sequence. There are 24 troops in the m+mi fj9kpn1 h lt+(qwr::- cnthird row and 42 troops in the sixth row.

1.Find the first term and the common difference of this arithmetic sequence.
u1 .
There are 15 rows in the battalion.

2.Find the total number of troops in the battalion.
S15 troops.

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25#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Charles has a New Years Resolution:jf jcs: qyw 6 ;jb*m*;dn(dhr that he wants to be able to complete 100 pushups in one go without a break. He sets out a training regime whereby he completes 20 pushups on the first day, then mdyw;nsr;jdh6 : f(* q:bj*cjadds 5 pushups each day thereafter.

1.Write down the number of pushups Charles completes
1.1.on the 4th training day;
u4 .
1.2.on the nth training day.

On the kth training day Charles completes 100 pushups for the first time.

2.Find the value of k.
k=  .
3.Calculate the total number of pushups Charles completes on the first 10 training days.
S10 .
Charles is also working on improving his long distance swimming in preparation for an Iron Man event in 12 weeks time. He swims a total of 10000 metres in the first week, and plans to increase this by 10 % each week up until the event.

4.Find the distance Charles swims in the 6th week of training.
v6≈  .
5.Calculate the total distance Charles swims until the event.
S12≈  m.

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26#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The number of seats fpnlmxtq s6jvd)e):x)2o( 8zin an auditorium follows a regular pattern where the first row haxmd f x2l6o)v pq:sze(n)t8j)s u1 seats, and the amount increases by the same amount, d, each row. In the fifth row, there are 62 seats and in the thirteenth row there are 86 seats.

1.Write down an equation, in terms of u1 and d , for the amount of seats
1.1.in the fifth row.
u5=u1 d

1.2.in the thirteenth row.
u12=u1 d

2.Find the value of u1 and d.
u1  ; d=   .
3.Calculate the total number of seats if the auditorium has 20 rows.
S20 .

The cost of the ticket for a musical held at the auditorium is inversely proportional to the seat's row. The price for a seat in the first row is 120 dollars, and the price decreases 3% each row. Thus, the value of the ticket for seats in the second row is 116.40 and 112.91 in the third one, etc.

4.1.Find the price of the ticket for a seat in the fifth row, rounding your answer to two decimal places.
p5 =   .

4.2.Find the row of the seat at which the price of a ticket first falls below 70.
n≈  .
4.3.Find the total revenue the auditorium generates by tickets sales if 40 seats in each of the 20 rows are sold. Give your answer rounded to the nearest dollar.
dollar=  .

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27#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Two college students, David and Lisa, decide to iwq ;wzxyle;j- wmp u0s6c:7 -pnvest money they have saved from working part-time jobs. David's investment strategy results in an increase of his investment amount by 1000 each yew: u lp;;xe jmwcqsyw-7z- p06ar. Lisa's investment strategy results in her investment amount increasing by 5% each year.

At the start of the second year of investing, David's total investment amount is 21000 and Lisa's is 11655.

1.Calculate
1.1.the original amount David invested.
u1 .
1.2.the original amount Lisa invested.
v1 .
During a certain year, n, Lisa's investment amount becomes larger than David's amount for the first time.

2.Find the value of n.
Lisa's amount will become larger than David's during year   .

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28#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Towards the end of 2004, a theatre q 4 )1s5o9zzkfrxz. s-pixddy5r.a7 mcompany upgraded their auditorium and installed new comfortable ergonomic chairs for the audience zrr)p5a.oxx7z- .i dfd9z 45msskq1y.

After the redesign, there were 20 seats in the first row and each subsequent row had three more seats than the previous row.

1.If the auditorium had a total of 16 rows, find
1.1.the total number of seats in the last row.
u16 seats.
1.2.the total number of seats in the auditorium.
S16 seats.
The auditorium reopened for performances at the start of 2005. The average number of visitors per show during that year was 500. In 2006, the average number of visitors per show increased by 5%.

2.Find the average number of visitors per show in 2006.
The average number of visitors per show continued to increase by 5% each year.
we get    visitors
3.Determine the first year in which the total number of visitors to a show exceeded the seating capacity of the auditorium.

The theatre company hosts 25 shows per year.

4.Determine the total number of visitors that attended the auditorium from when it opened in 2005 until the end of 2011. Round your answer correct to the nearest integer.
we get    visitors

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29#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Georgia is on vacation in Costa Rica. She is in a hot air ballo k7klu l,6) (f-*jdvtojj+fvnon over a lush jungle ikj,tv)vjfj(* d o6lu-7 knlf+n Muelle.

When she leans forward to see the treetops, she accidentally drops her purse. The purse falls down a distance of 4 metres during the first second, 12 metres during the next second, 20 metres during the third second and continues in this way. The distances that the purse falls during each second forms an arithmetic sequence.

1.1.Write down the common difference, d, of this arithmetic sequence.
d=  .
1.2.Write down the distance the purse falls during the fourth second.
u4 m.
2.Calculate the distance the purse falls during the 13th second.
u13 m.
3.Calculate the total distance the purse falls in the first 13 seconds.
S13 m
Georgia drops the purse from a height of 1250 metres above the ground.

4.Calculate the time, to the nearest second, the purse will take to reach
the ground.
n≈   seconds.
Georgia visits a national park in Muelle. It is opened at the start of 2019 and in the first year there were 20000 visitors. The number of people who visit the national park is expected to increase by 8% each year.

5.Calculate the number of people expected to visit the national park in 2020.
v2 .
6.Calculate the total number of people expected to visit the national park by the end of 2028.
S10 .

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30#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A ball is dropped from the top of the Eiffel Tower, 324 metrek,5* gwjum9z 7 5hsb4qjmlzj7s from the ground. The ball falu *jm 5bqmjjl479sz7h zwgk ,5ls a distance of 4.9 metres during the first second, 14.7 metres during the next second, 24.5 metres during the third second, and so on. The distances that the ball falls each second form an arithmetic sequence.

1.1.Find d, the common difference of the sequence.
d=  .
1.2.Find u5 , the fifth term of the sequence.
u5 m.
2.Find S6, the sum of the first 6 terms of the sequence.
S6 m.
3.Find the time the ball will take to reach the ground. Give your answer in seconds correct to one decimal place.
we obtain n ≈    seconds
Assuming the ball is dropped another time from a much higher height than of the Eiffel Tower,

4.find the distance the ball travels from the start of the 10th second to the end of the 15th second.
we get S=  m.
The Eiffel Tower in Paris, France was opened in 1889, and 1.9 million visitors ascended it during that first year. The number of people who visited the tower the following year (1890) was 2 million.

5.Calculate the percentage increase in the number of visitors from 1889 to 1890. Give your answer correct to one decimal place.
% increase=  %.
6.Use your answer to part (e) to estimate the number of visitors in 1900, assuming that the number of visitors continues to increase at the same percentage rate.
v12 million.

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31#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The first term of an arithmetic sequence is 24 and the common di ks r /qb+ei9rfky2h 9uj:b6i9fference is 16. 9k/9 q:kr ei+h 6b9u2sb rjfiy

1.Find the value of the 62 nd term of the sequence.
u62 .
The first term of a geometric sequence is 8. The 4th term of the geometric sequence is equal to the 13th term of the arithmetic sequence given above.

2.Write down an equation using this information.
8rx=y; x=  ; y=  .
3.Calculate the common ratio of the geometric sequence.
r=  .

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32#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Peter is playing on a swing during a school lunch breakcf;jq) bthq/5 . The height of the first swing was 2 m and every subsequent swing was 84 % of the previous one. Peter's friend, Ronald, gives hiqhj tqc 5;/b)fm a push whenever the height falls below 1 m.

1.Find the height of the third swing.
we find u3 ≈    m.
2.Find the number of swings before Ronald gives Peter a push.
Hence the swing needs a push after    swings.
3.Calculate the total height of swings if Peter is left to swing until coming
to rest.
S m.

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33#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Melinda has 300000 in a privanctl ) xa,wj7cg/5q*(4mvz- 0zfalvs te foundation. Each year she donates 10% of the money remaining in her private foundation to lcg vw,7aja4zvm(x t*q5s zc -)/ln0f charity.

1.Find the maximum number of years Melinda can donate to charity while keeping at least 100000 in the private foundation.
Hence the maximum number of years is   .
Bill invests $400000 in a bank account that pays a nominal interest rate of 4 %, compounded quarterly, for ten years.

2.Calculate the value of Bill's investment at the end of this time. Give your answer correct to the nearest dollar.
FV≈  .

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34#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A bouncy ball is dropped out of a second story classroom window, 5m off thesj0 oqn ,z s 9*3ur1asaev8eso7 4gv6s ground. Every time the ball hits the ground it bounces 89% of it 69v1 sg4rzsen7*eu q83sova 0j,sosas previous height.

1.Find the height the ball reaches after the 2nd bounce.
u2≈  m.
3.Find the total distance the ball has travelled when it hits the ground for the 5th time.
The total distance travelled by the ball is approximately    metres.

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35#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Landmarks are placed alon8osrt; hr-t z -hq-0jag the road from London to Edinburgh and the distance between each landmark is 16.1 km. The first milestone placed on the road is 124.7 km from London, and the last milestone is near Edinburgh. The length of the road from London to Edinburgh is 6 s0;jz- - r-htqa8ohrt67.1 km.

1.Find the distance between the fifth milestone and London.
u5 .
2.Determine how many milestones there are along the road.
Hence there are    milestones along the road.

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36#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  On September 1st, an orchard commences the process of harvesting 36 hectares of sl)k60ru; ttrpk8/gs e:pzdyx :ik//apple trees. At the end of September 4th, there were 30 hectares remaining to be harvested, and at the end of September 8th, there were 24 hectares remaining. Assuming that the number of hectares harvested each day is constant, the total num6ld k/0spite8r tg/;ksp / ky zr):x:uber of hectares remaining to be harvested can be described by an arithmetic sequence.

1.Find the number of hectares of apple trees that are harvested each day.
the orchard harvests    hectares of apple trees per day.
2.Determine the number of hectares remaining to be harvested at the end of September 1st.
at the end of September 1st, there are    hectares remaining to be harvested.
3.Determine the date on which the harvest will be complete.
the harvest will be complete at the end of September   th.

In 2021 the orchard sold their apple crop for 220000.Itisexpectedthatthesellingpricewillthenincreaseby3.24.Determinetheamountofmoneytheorchardwillearnfortheircropin2026.Roundyouranswertothenearestdollar.In2026,theorchardwillearn  .

for their crop.
5.1.Find the value of n=18(220000×1.032n1). Round your answer to the nearest integer.

5.2.Describe, in context, what the value in part (e) (i) represents.
The total amount earned for the apple crop from    to   
6.Comment on whether it is appropriate to model this situation in terms of a geometric sequence.
the selling price increases at a    rate annually.


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37#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Consider the sum S=k=4l(2k3),where l is a positive integer greater than 4.

1.Write down the first three terms of the series.
  ,  ,  
2.Write down the number of terms in the series.
It is   -  
3.Given that S=725, find the value of l.
l=  

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38#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Let un = 5n - 1, for n∈Z+.
1.1.Using sigma notation, write down an expression for u1+u2+u3+...+u10.
u1+u2+u3+...+u10=k=110(uk),uk -1
1.2.Find the value of the sum from part (a) (i).
the value of the sum=  .
A geometric sequence is defined by vn=5×2n1,for n∈Z+.

2.Find the value of the sum of the geometric series k=16(vk).
the sum of 6 terms formula,we get S6 .

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39#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Let un = 5n - 1, for n∈Z+.
1.1.Using sigma notation, write down an expression for u1+u2+u3+...+u10.
u1+u2+u3+...+u10=k=110(uk),uk -1
1.2.Find the value of the sum from part (a) (i).
the value of the sum=  .
A geometric sequence is defined by vn=5×2n1,for n∈Z+.

2.Find the value of the sum of the geometric series k=16(vk).
the sum of 6 terms formula,we get S6 .

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40#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The sides of a square are 8 cm long. A new square is fo:i5f(s awdh s5yq rm,0*hghe 0rmed by joining the midpoints of the adjacent sides and two of the resulting triangles are shaded as shown. This process is repeated 5 more times to form the right hand diagram below.0ds5aige( rw *q:f5h,hm hy0 s

1.Find the total area of the shaded region in the right hand diagram above.
the total area of the shaded region S≈  cm2
2.Find the total area of the shaded region if the process is repeated indefinitely.
Using the sum of an infinite geometric sequence formula S cm2

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41#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The half-life, T, in years, of a radioactive isotope can be/ yjszxpx; wpq*)3;a uu2+ rdf modelled by the function+ppx3zq *fr/; swu 2ydjx);au
ln0.5ln1k100 , 0​where k is the decay rate, in percent, per year of the isotope.

1.The decay rate of Hydrogen-3 is 5.5 % per year. Find its half-life.
T(5.5)≈  years
The half-life of Uranium-232 (U-232) is 68.9 years. A sample containing 250 grams of U-232 is obtained and stored as a side product of a nuclear fuel cycle.

2.Find the decay rate per year of U-232.
Solving the equation T(k)=68.9 for k, we obtain k=  %
3.Find the amount of U-232 left in the sample after:

(3.1) 68.9 years;
  grams
(3.2) 100 years.
u101≈  grams

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42#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The half-life, T, in days, of a radioactive isotope can be modellemi 7j/ cjx*cm,j:c2jmowip73d by the function pjcii2o mj7c*jc/x7,mjm3:w
ln0.5ln1k100,0
where k is the decay rate, in percent, per day of the isotope.

1.The decay rate of Gold-196 is 6.2 % per day. Find its half-life.
T(6.2)≈  days
The half-life of Phosphorus-32 (P-32) is 14.3 days. A sample containing 120 grams of P-32 is produced and stored in a biochemistry laboratory.

2.Find the decay rate per day of P-32.
Solving the equation T(k)=14.3 for k, we obtain k=  %
3.Find the amount of P-32 left in the sample after:
3.1.
14.3 days;   grams

3.2.
50 days. u51≈   grams

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43#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Elon is challenged to a speed climb at a l6ex- ;j 4flhblocal mountain. He has to reach a height of 400 mee6- xfjlb;4 hltres above the ground within four hours.

Elon knows he can climb 150 metres in the first hour. Due to increasing tiredness, each hour he can only climb 75% of the height climbed in the previous hour.

1.Verify that Elon reaches his target height of 400 metres in four hours.
S4≈  m
The mountain has a height of 650 metres. Elon decides to attempt to climb to the summit.

2.Determine whether he can reach the summit of the mountain if he continues climbing, given his increasing tiredness. Justify your answer.
S m
On a different day, Elon climbs with energy snacks, which help to reduce his tiredness as he climbs. On this day, Elon again climbs 150 metres in the first hour, but then k% of the height he climbed in the previous hour, where k>75.

3.Calculate the minimum value of k, given that on this day Elon is able to reach the summit. Give your answer as a percentage, to the nearest whole number.
The minimum value of k is    %

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44#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Consider the sequencpw5 rl3a-ppg *e u1 , u2 , u3 , ... , un , ... where
u1=860, u2=980, u3=1100, u4=1220.
The sequence continues in the same manner.
1.Find the value of u50.
u50 .
2.Find the sum of the first 10 terms of the sequence.
S10 .
Now consider the sequence v1 , v2 , v3 , ... , vn , ... where
v1=2, v2=4, v3=8, v4=16.
This sequence continues in the same manner.
3.Find the exact value of v13.
v13 .
4.Find the sum of the first 10 terms of this sequence.
S10 .
k is the smallest value of n for which vn is greater than un.

5.Calculate the value of k.k=  .

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45#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  On Wednesday Eddy goes to a velodrome to train. He cycles the first lap of the h u7sov7tq:*ftqu h7o*s7tf:v rack in 25 seconds. Each lap Eddy cycles takes him
1. 6 seconds longer than the previous lap.

1.Find the time, in seconds, Eddy takes to cycle his tenth lap.
u10 seconds.

Eddy cycles his last lap in 55.4 seconds.

2.Find how many laps he has cycled on Wednesday.
n=  laps.
3.Find the total time, in minutes, cycled by Eddy on Wednesday.
S20 minutes.
On Friday Eddy brings his friend Mario to train. They both cycled the first lap of the track in 25 seconds. Each lap Mario cycles takes him 1.05 times as long as his previous lap.

4.Find the time, in seconds, Mario takes to cycle his fifth lap.
v5≈  seconds.
5.Find the total time, in minutes, Mario takes to cycle his first ten laps.
S10≈  minutes
Each lap Eddy cycles again takes him 1.6 seconds longer that his previous lap.
After a certain number of laps Eddy takes less time per lap than Mario.

6.Find the number of the lap when this happens.
n=  th lap

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46#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A bouncy ball is dropped from a height of 2 metres onto a concrete floor. After v8s,te6 lhl 8c;eo9bm .t8jlchitting the floor, thmcsh8, ejbte 9tco6 ;l.lv 8l8e ball rebounds back up to 80 % of it's previous height, and this pattern continues on repeatedly, until coming to rest.

1.Show that the total distance travelled by the ball until coming to rest can be expressed by
2+4(0.8)+4(0.8)2+4(0.8)3+...

2.Find an expression for the total distance travelled by the ball, in terms of the number of bounces, n.

3.Find the total distance travelled by the ball.S=  metres.

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47#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A bouncy ball is dropped outuub)rd/qb--:tm( h hz of a second story classroom window, 5 m off the ground. Every time the ball hits the ground m:b-/ubht()dzh qu-r it bounces
89 % of its previous height.

1.Find the height the ball reaches after the 11th bounce.
u11≈  m.
2.Find the total distance travelled by the ball until it comes to rest.
total distance travelled≈  m.

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