The area A is defined as the region bounded by tpw -cxngecj, 0p+uf*8he curve y=$-\frac{x^{2}}{6}(x-6)$ and the x -axis for $0 \leq x \leq 6$ .
1. Sketch the curve on the diagram below, shading the area A .

2. Write down a definite integral that represents area A .
3. Find the area of A .
[Area A]=   units$^2$

  The area A is defined as thu4/sw;a w- v cczk7.fq5k e-aee region bounded by the curve y=$-\frac{x^{2}}{5}(2 x-5) $ and the x -axis for $ 0 \leq x \leq \frac{5}{2}$ .

1. Sketch the curve on the diagram below, shading the area A .

2. Write down a definite integral that represents area A .
Area A=$\int_{0}^{5 / 2}-\frac{x^{2}}{5}(2 x-5) \mathrm{d} x$ ;a=  ,b=  .
3. Find the area of A .
Area A=$\frac{a}{b}$ units$^2$ ; a=  ,b=  .

  The equation of a curve if*4xq2w.vm sqzy k. k;s y=-$x^{3}+4 x^{2}+x-4$ . A section of the curve is shown on the diagram below, with the three x -intercepts labelled.

1. Find $\frac{\mathrm{d} y}{\mathrm{~d} x}$ = - ax$^2$+ bx+c ; a=  ,b=  ,c=  .
2. Write down the coordinates of the local maximum.
3. Write down an integral representing the area of the shaded region.
A=$\int_{1}^{4}\left(-x^{3}+a x^{2}+x-b\right) \mathrm{d} x$;a=  ,b=  .
4. Find the area of the shaded region.
A=$\frac{a}{b}$;a=  ,b=  .

  The equation of a curve is y=-rxjy90.2y4i 8nr c+7 hntszwp$x^{2}+8 x-12$ . A section of the curve is shown on the diagram below, with the two x -intercepts labelled.

1. Find $\frac{\mathrm{d} y}{\mathrm{~d} x}$ = -ax + b; a=  ,b=  .
2. Write down the coordinates of the local maximum, the local maximum is located at (  ,  )
3. Write down an integral representing the area of the shaded region.
4. Find the area of the shaded region.
A=$\frac{a}{b}$ units$^2$;a=  ,b=  .

  Let f(x)=$2 x e^{x} $ and g(x)=-2 f(x)-1 .
The graphs of f and g intersect at x=a and x=b , where a ＜ b

1. Find the value of a and of b .
2. Hence, find the area of the region enclosed by the graphs of f and g .
A=  .

  A reservoir of watergjljug 4:hutc6*:o 2n has a cross-sectional area shown in the shaded region of the diagram below, where x and y values are in metres. The bottom of the reservoir (the curve shown) has an equation ihjt gc24lg* u:jo6:nu n the form

$y=k(x-8)^{2}$

1. Find the area of the rectangle OMNP, The area of the rectangle OMNP is determined by A$_1$=   m$^2$.

2. Determine the value of k is $\frac{a}{b}$;a=  ,b=  .
3. Find the cross-sectional area of the reservoir.
The number is    m$^2$.

  A section of the curve with equation y=2(x-3)(x+8) ihk/.,j8n)j bbhg t: fys shown.

1. Write an integral for the shaded area A.
[Area A] = $\int_{a}^{b} 2(x-3)(x+8) \mathrm{d} x$; a=  ,b=  .
2. Find the area of A is    units$^2$ .
3. Find the area of B is    units$^2$ .

  The following diagram sho dzl83 syj/qp-ws the parabolic shape of a gateway arch that has a span of 12 metres and a maximum height of 8 metresdzyq pjl3 /-8s.

The curve has an equation in the form y=$k(x-6)^{2}+8$ .
1. Determine the value of k is $\frac{a}{b}$;a=  ,b=   .
2. Write down an integral that represents the cross sectional area under the arch shown as OMN.
A=$\int_{0}^{12}\left[-\frac{a}{b}(x-6)^{2}+c\right] \mathrm{d} x$;a=  ,b=  ,c=  
3. Find the cross sectional area under the arch.Evaluating the integral in part (b), we get a=   m$^2$.

  Let f(x)=$9-2 \ln \left(x^{2}+4\right) $, for $x \in \mathbb{R}$. The graph of f passes through the point (p, 3) , where p>0 .
1. Find the value of p is   .

The following diagram shows part of the graph of f .

The region enclosed by the graph of f , the x -axis and the lines x=-p and x=p is rotated $360^{\circ}$ about the x -axis.
2. Find the volume of the solid formed is   .

  Consider the region enclosed by the gr j7w/;omb h2cqaph of the function f(x)=$e^{x / 2}$ , the x -axis and the vertical lines x=0 and x=3 .
1. Sketch the function f and shade in the region.

2. 1. Write down a definite integral that represents the shaded region, it is $\text { 1. } \int_{a}^{3} e^{x / b} \mathrm{~d} x \backslash$,a=  ,b=  .
2. Calculate the area of the shaded region is   .
3. Use the trapezoidal rule with n=6 trapeziums to estimate the area of the region.

  Let f(x)=$\frac{1}{\sqrt{3 x-6}}$ , for x>2
1. Find $\int(f(x))^{2} \mathrm{~d} x$ = $\frac{1}{a} \ln (b x-6)$+C;a=  ,b=  .

Part of the graph of f is shown in the following diagram.

The shaded region R is enclosed by the graph of f , the x -axis, and the lines x=3 and x=11 .
2. Find the exact volume of the solid formed when R is rotated $360^{\circ}$ about the 3 x -axis.
V= $\frac{\pi}{a}$$ln_{b}$,a=  ,b=  .

  On the Persian Gulf, there is a small peninsula that can be modelled by the equc2b 6l36gffzc ation g 66fbl32cczf y=$-0.2 x^{3}+1.2 x^{2}-x$ where x and y are measured in kilometres, as shown in the following diagram. Points $\mathrm{P}$ and $\mathrm{Q}$ are on the coastline.

1. Find the coordinates of $\mathrm{P}$ is (  ,  ) and $\mathrm{Q}$ is (  ,  ) .
2. Find the furthest distance that the land protrudes from the coastline.
3 . Find the area of the peninsula，The area of the peninsula is given by A=   km$^2$.

  The graphs of y=-0.5 x+2.5 anx-dspnly;n-kx( + g; ud $y=0.5 x^{2}+0.5 x+1$ intersect at (-3,4) and (1,2) , as shown in the following diagrams.

1. Calculate the shaded area in diagram 1 , the area enclosed by the lines y=-0.5 x+2.5 x=-3, x=1 and the x -axis, A$_1$=   units$^2$
2. 1. Write down an integral for the shaded area in diagram 2 , the area enclosed by the curve y=$0.5 x^{2}+0.5 x+1$ , the lines x=-3 and x=1 , and the x -axis.
A$_2$=$\int_{-3}^{1}\left(0.5 x^{2}+0.5 x+a\right) \mathrm{d} x$;a=  .
2. Calculate the area of this shaded region,A$_2$≈   units$^2$
3. Hence, determine the area enclosed by the line y=-0.5 x+2.5 and the curve y= $0.5 x^{2}+0.5 x+1$

  A curve y=f(x) has49mdtj, qq8tsl, m:rx a gradient function of f^{\prime}(x)=a x+1 . The diagram below shows part of the curve, with the x and y intercepts labelled.

1. Find the equation of the curve is y=-ax$^2$+bx+c; a=  ,b=  ,c=  .
2. Find the area under the curve from 0A=$\frac{a}{b}$units$^2$,a=  ,b=  .

  A curve y=f(x) has a gradient function of *trk0iso1agt.vjj7 7 $f^{\prime}(x)=a x+5 $. The diagram below shows part of the curve, with the x and y intercepts labelled.

1. Find the equation of the curve,y=$-ax^2+bx+c$;a=  ,b=  ,c=  .
2. Find the area under the curve from 0 ,b=  .

  The shape of a bowl is given by revolving the curve t,*w6t imafy 76v0vjwwfy:)a y=$\frac{1}{3} x^{\frac{7}{4}}$, $0 \leq x \leq 6 through 360^{\circ}$ about the y -axis. The units are in centimetres.

1. Find the height of the bowl.
h≈   cm.(Two decimal places)
The bowl is completely filled with water.
2. Find the volume of water in the bowl.
V≈   cm$^3$(round number)

  The following diagram s88g5.reln f yihows the graph of the function $f(x)=\frac{b}{a} \sqrt{a^{2}-x^{2}}$

Find an expression, in terms of a and b , for the volume of the solid formed by rotating the curve $360^{\circ} $ about the x -axis.
we get V=$\frac{x{\pi}ab^2}{y}$;x=  ,y=  .

  The following table shows the rate, R , at which rubb1(viyuzu/3u vv,hw ,p ish is produced by a town, in to, u,uwzv/h1yupi3 vv(nnes per day. t represents the time in days since the rate of rubbish production was first recorded.

The total amount of rubbish produced by the town over the 3-day period is equal to the area underneath the graph of the curve R(t) .

1. Use the trapezoidal rule with 6 intervals to estimate the total amount of rubbish produced by the town over the 3-day period；The total amount of rubbish produced is approximately    tonnes (round number please)

The actual amount of rubbish produced over the 3 days was 191 tonnes.
2. Find the percentage error between the estimate in part (a) and the actual amount of rubbish produced;The percentage error between the estimate in part (a) and the exact value can be found using the percentage error formula is close to   % (tow decimal please)

  A curve y=f(x) passes throug8q1 7vtthgqk*0 sep0bys h9: rh point $\mathrm{P}$(2,7) and has a gradient of $ f^{\prime}(x)= 4 x-3 $.
1. Find the gradient of the curve at point P ;f(x)=  .
2. Find the equation of the tangent to the curve at point P; y=kx-b,k=  ,b=  .
3. Determine the equation of the curve; the equation of the curve is y=ax$^2$-bx+c;a=  ,b=  ,c=  .

  The following diagram shows part of the graph of fo4 j-xa:6as sy u+j,m5jvge/s (x)=\left(16-x^{2}\right)(x+ 3 ), x \in \mathbb{R} . The shaded region R is bounded by the x -axis, y -axis and the graph of f .

1. Write down an integral for the area of region R ;[Area R] = $\int_{0}^{4}\left(a-x^{2}\right)(x+b) \mathrm{d} x$;a=  ,b=  .
2. Find the area of region R ; [Area R]=    units$^2$

A trapezoid A B C D has four vertices with the coordinates shown as below.

3. Find the value of a , the x -coordinate of point $\mathrm{D}$ , such that the area of the trapezoid is equal to the area of region R .
Since the area of the trapezoid ABCD is equal to the area of region R, we get a is   .

  The following diagram shows part of zwzjj9c0;1 cb the graph of f(x)=$x^{3}-3 x^{2}-4 x+ 12$, $x \in \mathbb{R}$ . The shaded region R is bounded by the x -axis, y -axis and the graph of f .

1. Write down an integral for the area of region R ；[Area A]=$\int_{-2}^{0}\left(x^{3}-a x^{2}-4 x+b\right) \mathrm{d} x$;a=  ,b=  
2. Find the area of region R is    units$^2$

A parallelogram A B C D has four vertices with the coordinates shown as below.

3. Find the value of a , the y -coordinate of points $\mathrm{B} $ and $ \mathrm{C}$ , such that the area of the parallelogram is equal to the area of region R . a=  .

  A company is going to make an excavation to access a m7yk udeuv 2/nd8a+cs(ine. The cost of excavatin7 euu2k/yd+asv dc(8 ng is \$ 12 per $\mathrm{m}^{3}$ . The following table shows an estimate of the areas of horizontal crosssections, at 5 -metre intervals, of the underground to be removed where the height is measured in metres below the ground level.


1. Use the trapezoidal rule to find an estimate of the volume of ground to be removed，we obtain the V ≈   m$^3$ (round number)
2. Hence, or otherwise, estimate the total cost of excavation;The total cost of excavation is $\$$   .
​

  A piece of jewellery is being designed for an auction. Its shape is based on 3p)1jp2raohsi98ua5q /znxw: h* a ucthe graph opuxwo q:*arpn 5 zh1as9ua)i2h /jc38f

$y=\frac{x}{50} \sqrt{625-x^{2}} \quad \text { for } 0 \leq x \leq 25$

which is revolved $360^{\circ}$ about the x -axis, where x and y are measured in $\mathrm{mm}$ .

1. Find the area bounded by the graph and the x -axis.
Area ≈   .
2. Hence or otherwise, find the volume of the jewel is(≈)   mm$^3$.
3. If $1 \mathrm{~cm}^{3}$ of silver weighs 10.5 grams, and 1 gram of silver costs $\$ 1.50$ , find the cost of the silver used for the jewel to the nearest dollar is(≈)   .

  Rain is filling an empty water reservoir at a rate of r litres per minute, w5h e*8bobx- zchere r=bhe*x8o bcz-5$\frac{t}{5}$ and t is the time measured in minutes. The graph of this is shown below.

1. Find how much water has filled the reservoir after 1 hour ; we get V=    L
2. Determine an expression for the amount of water that has filled the reservoir for any given number of minutes, m ;The volume of water that has filled the reservoir after m minutes can be expressed as V=$\frac{a}{b}$m$^2$ (L);a=  ,b=  .

  The following diagram shows the graph of f(x)=:qiv+89m4xg o- o eikq$\frac{4 x}{x^{2}+1}$ , for $0 \leq x \leq 6$ , and the line x=6 .

Let R be the region enclosed by the graph of f , the x -axis and the line x=6 .
1. Show that $\int f(x) \mathrm{d} x=2 \ln \left(x^{2}+1\right)+C$ .
2. The exact value for the area of the region R is $\ln k$ , where k is a positive integer. Find the value of k is   .

  The diagram below shows the graphsqn*;w+qq8e lqv9(sr s of functions $y=4-2 x^{2}$ and $y=2 x^{3} $.

1. Find the volume resulting from a rotation of the shaded region shown in the diagram through $2 \pi $ about the x -axis.
V≈   .( one decimal pleaces)
2. Find the volume resulting from a rotation of the region shown in the diagram through $2 \pi $ about the y -axis.V≈   .( two decimal pleaces)

  The diagram below shows the:-6g ) )b otvnshlch4u graphs of functions $y=5-3 x^{3}$ and $y=2 x^{4}$ .

1. Find the volume resulting from a rotation of the region shown in the diagram through $2 \pi$ about the x -axis.V≈   (one decimal pleaces)
2. Find the volume resulting from a rotation of the region shown in the diagram through $2 \pi $ about the y -axis.V≈   (two decimal pleaces)

  Bellatrix Aviation manufactures1-j 0x6w,zu9)urb2kxi1:bz btasg ft business jets. The profit the company makes, P , in millions of dollars, changes based on the number of jets, x , they manufacture per kruuaf 1b0bx: - i t9j gswb61xz,t2z)quarter.
The rate of change of the profit made from manufacturing x jets is modelled by

$\frac{\mathrm{d} P}{\mathrm{~d} x}=-0.4 x+16, \quad x \geq 0 $.


In the previous quarter, the company made a profit of 165 million dollars from manufacturing 20 jets.
1. Find an expression for P in terms of x .Therefore we obtain P= $-{a}x^2 + b x - c$;a=  ,b=  ,c=  .

The company has the capacity to increase the number of jets they manufacture.
2. Describe how the profit changes if the company increases manufacturing to over 40 jets per quarter and up to 75 jets per quarter.

  The water in a pool is being pumped out into a nearbs tvl v o3)m4z,jss4f2y lake at a rate of r litres pjvovs4l f2)s s 4,z3tmer second where r=$\frac{2 t}{275}$ and t is time measured in seconds. The graph of this is shown below.

1. Find out how much water has been pumped out after 1 minute,We get V≈   L
2. Determine an expression for the volume of water that has been pumped out of the pool for any given number of seconds, s ;The volume of water that has been pumped out of the pool after s seconds can be expressed as
v=$\frac{a}{b}$s$^2$ (L) ;a=  ,b=  .

  Consider the region R enclosed by the curve x5sykb3onr0k i+lk( ) $y=-3(x-2)(x-8)$ and the x axis.

1. Sketch the curve and shade the region R on the following axes.

2. 1. Write down an integral that represents the area of region R ;The area of region
R is determined by A=$\int_{2}^{8}-a(x-2)(x-b) \mathrm{d} x$ ;a=  ,b=  .
2. Find the area of region R is    units$^2$.
3. Estimate the area of region R using five trapezoids.
4. Find the percentage error between the exact value found in part (b)(ii) and the estimation in part (c);The percentage error between the estimation in part (c) and the exact value in part (b)(ii) can be found using the percentage error formula [% error]=   %

  Let f(x)=$x(x-3)^{2}$ , for $0 \leq x \leq 4$ . The following graph shows f .

Let R be the region enclosed by f , the x -axis and the lines x=0, x=3 .
1. Show that $\int f(x) \mathrm{d} x$=$\frac{x^{4}}{4}-2 x^{3}+\frac{9 x^{2}}{2}+C$.
2. Find the volume formed when R is rotated $360^{\circ}$ about the x -axis ;The volume is given by the integral V=   .
3. The diagram below shows part of the graph of the quadric function g(x)=x(a-x) . The graph of g crosses the x -axis when x=a .

The area enclosed by the graph of g is equal to the area of R . Find the value of a is   .

  BioNature Inc. is considering the monthly cost of producx01wf0 ngj.ag ums,l +ing straws made from paper. It is estimated tl001usx+f, amnj w.gg hat the rate of change in monthly cost with respect to the number of paper straws produced is modelled by

$C^{\prime}(q)=0.006 q^{2}-0.48 q-12, \text { for } q>0$

Where the monthly cost, $ \$ C$ , is in thousands and the number of straws, q , is also in thousands.
1. Find the number of paper straws that the company should produce in a month to minimize the cost.

The company produces 110000 paper straws with a cost of $\$ 88000$ in a certain month.
2. Find an expression for C in terms of q ;we obtain C(q)=$0.002 q^{3}-aq^{2}-12 q+b$;a=  ,b=  

  A healthcare company is designing a new deodorant stick th r4y/ qbn*iipb ,7rpec.)h)kuat can be modelled by the shape of a parabola as the top, vertical lines as the sides and a horizontal line as the base, on the x -axis. Th))4 ib*bip yre7 hq/u,prk.nce parabola has end points at (0,7) and (5,7) , and vertex at (2.5,8) .
This design is shown in the diagram below. All distances are measured in centimetres.

The quadratic curve can be expressed in the form y=$a x^{2}+b x+c$ for $0 \leq x \leq 5$ .
1. 1. Find the value of c is  .
2. Using the points (2.5,8) and (5,7) , write two equations in a and b .
3. Hence, find the equation of the quadratic curve; we get y=-ax$^2$+bx+c;a=  ,b=  ,c=  .
2. Find the area of the shaded region in the deodorant design.

  Water is pumped from a river basin into an irrdw5 4+x h.+egsm;m z+0iw jwl;ow sol-igated field at a rate of r=\fracm sws+-jwd+owhil z4 5o. lx+;ew;0mg{t^{2}}{25} where r is measured in cubic metres of water per minute and t is the time measured in minutes. The graph of this is shown below.


1. Write down an integral that represents the area of the shaded region. It is A =$\int_{0}^{60} \frac{t^{2}}{a} \mathrm{~d} t$ ;a=  .
2. 1. Find the area of the shaded region is    m$^2$.
2. Interpret the meaning of the shaded area in the context of this question.
3. Find the number of minutes it takes to pump 500 $\mathrm{~m}^{3}$ of water into the field.
m≈   min (one deciaml pleaces).

  The following diagram shows a section of a curve y=f(x) and the jo 4a t9jyaoa,*v/qg/ coordinates of six points that lie on the cur a/tj4,jvgao9/y aq o*ve.


1. Estimate the area of the shaded region, giving your answer to two decimal places.
$\int_{1}^{5} y \mathrm{~d} x$ $\approx$    units^2
The equation of the curve was found to be y=2 $x^{2}-4 x+20$ .
2. Write an integral that represents the area of the shaded region.
A= $\int_{1}^{5}\left(a x^{2}-b x+c\right) \mathrm{d} x$; a=  ,b=  ,c=  .
3 . Find the area of the shaded region, giving your answer in exact values.
A=$\frac{a}{b}$ $units^2$ ; a=  ,b=  .
4. Find the percentage error between the estimation in part (a) and the exact value found in part (c).

  The diagram below shows part of the graphs 0)5ljawxw2 2 p2oeehmof y=$(x+2)^{2}$ and y=$(6-x)^{2}$ .

1. Find the coordinates of the points P, Q and R .
P is (  ,  ) ;Q is (  ,   ) ;R is (  ,  )
The shaded region is rotated through $360^{\circ}$ about the x -axis.
2. Calculate the volume of the solid obtained.

  Consider the region R el/ywc-a,qs5n):9 eb7e oe f5z+fq v srnclosed by the curve y=$\frac{1}{2}(x+2)(x-3)$ and the x -axis.
1. Sketch the curve and shade the region R on the following axes.


2. 1. Write down an integral that represents the area of region R .
2. Find the area of region R is A ≈   units$^2$(one decimal please)
3. Estimate the area of region R using five trapezoids.
it is ≈    $units^2$ (round number)
4. Find the percentage error between the exact value found in part (b)(ii) and the estimation in part (c).

  In a memory competition, the rw:z4a97zz5xt p kfv8 4xqy u8yate at which English speaking participants memorise Frenc 8x4 qakx8fzvyu:yzpw4tz5 97 h vocabulary can be modelled by the equation

$\frac{d M}{d t}=1-0.01 t$, $\quad t \geq 0$,

where M(t) is the number of words memorised in t minutes.
The number of words participants have memorised at the beginning of the competition, t=0 , is zero.
1. Find the equation for the number of memorised words at time t . M(t)= t - a$^{-3}$ t$^2$ ; a=  .

The competition ends when students get so tired that the number of additional memorised words per minute becomes zero.
2. Find the value of t when the competition will end.
t=   minutes.
3. Determine
1. the domain of M(t) is [  ,  ],
2. the range of M(t) is [  ,  ].

  Kai launches stones from a slingshot into th)yi-ee:kjl nm.; 1qvr e air. Each time he launches a stone, he records the angle, \theta , in degrees, at which the stone is launched, and the horizontal distance, L , in metres, which the stone travels from his shooting position to where it first lands. The diagram below illustrates how the stones travel in the air when launched at diffqjmnye1 ;kei )- r:l.verent angles.


Kai analyses his results and concludes:

$\frac{\mathrm{d} L}{\mathrm{~d} \theta}=-0.08 \theta+3.3, \quad 0^{\circ} \leq \theta \leq 90^{\circ}$ .

1. Determine whether the graph of L versus \theta is  ----待选择----increasing decreasing  at $\theta= 50^{\circ}$ .

Kai observes that when the angle is $30^{\circ} $, the sling stone will travel a horizontal distance of $90 \mathrm{~m}$ .
2. Find an expression for L in terms of $\theta$ .
L= -0.04$\theta$$^2$+ a$\theta$+b ;a=  ,b=  .

  The cross-sectional view of a two-lane road5peyg41l 5xg8lq7sg )wbmq b0 tunnel system is shown on the axes below. The lbw8qg7g5s0 y54b epmxq)llg 1eft and right lane tunnels are separated by a 2 metre thick concrete wall. The right-hand tunnel passes through the points $\mathrm{A}$, $\mathrm{B}$, $\mathrm{C}$ and $\mathrm{D}$ and its height, in metres, above the base of the tunnel, is modelled by f(x)=-$0.04 x^{3}$+ 0.41 $x^{2}$, $4 \leq x \leq 10$ , relative to an origin $\mathrm{O} $.


Point A has coordinates (4,4) and point $\mathrm{D}$ has coordinates (10,1) .
1. Find the height of the right-hand tunnel when:
1. x=6 ; f(6)=   (m)
2. x=8 ; f(8)=   (m)
The left-hand tunnel can be modelled by a function g(x) , found by reflecting f(x) in the line x=3 .

2. Find the equation of g(x) .g(x)=$0.04 x^{3}-a x^{2}-bx+6.12$;a=  ,b=  .

3. 1. Find $g^{\prime}(x)$ .$g^{\prime}(x)=ax^{2}-b x-0.6$;a=  ,b=  .
2. Hence find the maximum height of the left-hand tunnel.
4. 1. Write down an integral which can be used to find the cross-sectional area of the left-hand tunnel.
2. Hence find the combined cross-sectional area of both tunnels.

  A fire truck is pumping water at a rate o,: gb*kfw4 e jc3pd.-zbg)gcof r=$\frac{2 t^{2}}{35}$ where r is in litres per second and is the time measured in seconds.
The graph of r is shown below.

1. Write down an integral that represents the area of the shaded region.
$A=\int_{x}^{y} \frac{a t^{2}}{b} \mathrm{~d} t$;a=  ,b=  ; x=  ,y=  .
2. 1. Find the area of the shaded region, rounding your answer to the nearest whole number.
2. Interpret the meaning of the shaded area in the context of this question.
3. Calculate the number of seconds it takes for the fire truck to pump $1000 \mathrm{~L}$ of water.
s≈   s (one decimal plaeaces)

  The diagram below shows the cross-sectional area of a mound l yj+q ;fdt3: 6au14 lxgtz,b7krt/ wjof beach sand created after a hiq64bfj/ ,;3 da7zw:xlgtju lt krty 1+gh tide.


The curve of the cross section can be modelled by the following equation

$y=\frac{x^{2}(90-x)}{1800}$

where y represents the vertical height of the mound in $\mathrm{cm}$ and x denotes the horizontal width in $\mathrm{cm}$ , from the start of the mound.
1. At a horizontal width of x=30 , determine
1. The vertical height of the mound at this point; y=   cm.
2. The gradient of the mound curve at this point. y'=$\frac{a}{b}$;a=  ,b=  .
2. 1. Find the value of x which corresponds to the maximum the vertical height of the mound;it is   .

2. Hence, find the maximum vertical height of the mound. y=   cm
3. Calculate the cross-sectional area of the mound, rounding your answer to one decimal place.

A child uses a toy shovel to remove the top of sand mound, as illustrated by the line segment $\mathrm{MN}$ below. Point M has coordinates at (30,30) .

4. Determine the coordinates of point N .

The cross-sectional area removed by the child can be expressed by the following integral

$\int_{p}^{q} \frac{x^{2}(90-x)}{1800} \mathrm{~d} x-R$,

5. Determine the values of p, q and R . p=  ; q=  , R=  .

  The following table shows the x and y coordinates of five poiuk 3-t)5 n;zkop jzp7wnts that lie on 7)-jptpzk 5 o3zwn ;uka curve y=f(x) .


1. Estimate the area under the curve over the interval 2
The equation of the curve was found to be y=$x^{3}-7 x^{2}+14 x-2$ ;it is Approximately equal to    units$^2$( one decimal please)
2. 1. Write down an integral that represents the area under the curve over the interval.
2. Find the exact value of the area under the curve over the interval.A=$\frac{a}{b}$;a=  ,b=  .
3. Find the percentage error between the estimation in part (a) and the exact value in part (b). Provide a reason for the difference.

  The following table shows the x and y coordinates opr1orkxj)6 p/rzp+ 8 n)h8l st p;)xdwf five points that lie on a curve y=p)sj rh tx;8r1op/)lkn68rpd+p z) x wf(x) .

1. Estimate the area under the curve over the interval 1
The equation of the curve was found to be y=-$\frac{1}{10}(4 x+5)(x-8)$ .
it is approximately equal to    units$^2$

2. Find the exact value of the area under the curve over the interval 1A=$\frac{a}{b}$;a=  ,b=  .
3. Find the percentage error between the estimation in part (a) and the exact value in part (b). Provide a reason for the difference.it is approximately equal to    %(two decimal places)

  During a trip to a forest to forage for mushrooms, Viviane finds a giantr thb3v1m lfbc2nmes x* a-wr/)jy3*. mushroo.nt /h*1frbyj bvrc3 e )ma-swm*2l3xm. She decides to model the shape of the mushroom to find its volume.

After taking a photo of the mushroom and zooming in to get its real size, she rotates the photograph and estimates that the cross-section passes through the points (0,3) (15,3),(15,15),(22,10),(23.5,6) and (24,0) , where all measurements are in centimetres. The cross-section is symmetrical about the x -axis, as shown below.

Viviane models the section from (0,3) and (15,3) with a straight line.
1. Write down the equation of the line that passes through these points.
y=  .
Next, Viviane models the section that passes through the points (15,15),(22,10) , (23.5,6) and (24,0) with a quadratic curve. it is (  ,  )
2. 1. Use your G.D.C. to find the equation of this quadratic curve.
y≈-1.82(x-a)$^2$+a;a=  .
2. By considering the gradient of the curve at the point (15,15) , explain why this may not be a good model.

Viviane thinks she can obtain a better model if a quadratic passing through the point (24,0) with a maximum point at (15,15) is used.
3. Find the equation of this model, in the form y=a(x-h)^{2}+k .

Using this new model, Viviane proceeds to estimate the volume of the mushroom by finding the volume of revolution about the x -axis.
4. 1. Write down an expression for her estimate as a sum of two integrals.
2. Find the volume of the mushroom estimated by Viviane.
V≈   cm$^2$ (round number)

  Lohan receives an antique vase as a gift from her gra4l ed b 8mt,aw//rp3dsndparents. She decides to model the shape of the vase to calculate itsl 4e/3adsbtp mdw,r 8/ volume.

She places the vase horizontally on a piece of paper and uses a pencil to mark five representative points (0,5),(7.5,10),(17,7.5),(25,3) and (35,7.5) , as shown below. These points are connected to form a symmetrical cross-section about the x axis. All units are in centimetres.


Lohan initially uses a straight line to model the section from (25,3) to (35,7.5) .
1. Determine the equation of the line that passes through these two points.
y=ax-b;a=  ,b=  .
Lohan thinks that a quadratic curve might be a good model for the section from (0,5) to (25,3) . She carries out a least squares regression using this model for the points she has recorded.
2. 1. Determine the equation of the least squares regression quadratic curve found by Lohan.
2. By considering the gradient of the curve at the point where x=10 , determine whether the quadratic regression curve is a good model or not.

Lohan decides that a cubic curve for the entire section from (0,5) to (35,7.5) would be a better fit.

3. Find the equation of the cubic model.

Using this model, Lohan estimates the volume of the vase by calculating the volume of revolution about the x -axis.
4. Find the volume of the vase estimated by Lohan.

Lohan subsequently fills the vase with water and discovers that the true volume is 5500 $\mathrm{~cm}^{\wedge} $3 .
5. Calculate the percentage error in Lohan's estimate of the volume.
Using the formula for percentage error, we have
ϵ=  %
​

  A function is given by uara u,2fu/ 1g$f(x)=4 x^{3}-x for -\frac{1}{2} \leq x \leq \frac{1}{2}$ .
1. Sketch the graph of f for the given domain, labelling all intercepts and stationary points.

2. Find an approximation for $I=$\int_{0}^{1 / 2} f(x) \mathrm{d} x$$ using the trapezoidal rule with a strip width of 0.1 .
3. Find the exact value of I in part (b).The exact value of I is -  
4. Explain why the approximation found in part (b) is larger than the exact value found in part (c).
5. Write down the value of $J=\int_{-1 / 2}^{1 / 2} f(x) \mathrm{d} x$ without calculation. Give a reason for your answer.
I=  .

  The table below shows the daily revenue, R , in thousands of USD, of a et3tym gbk0fl7. 4qs5 toy store during the month of December. The first row of the table shows the day of the month (t ) and the second row the revet307 .s ylgmkfqbe45tnue of that day in thousands of USD.

1. 1. Generate a scatter diagram for this data on the axes below.

2. Identify a possible outlier and give a possible reason for this outlier;
3. Give a reason why plotting R vs $ \log (t)$ is likely to be the best linearisation method.
2. Linearise the data and determine an appropriate linear model for the daily revenue R in terms of day of the month in December, t .
3. Using your model, predict the revenue after 3 weeks in December.
4. The total revenue for the month of December can be estimated by $ \int_{a}^{b} R \mathrm{dt}$ .
1. Write down the values of a and b .a=  ,b=  .
2. Estimate the total revenue in December using your model.
TR≈    thousads of USD

  A company that manufactures and sells cardboard boxes has a box with a ysnfq,/mps1*i;l d0v n open-top design. This box is constructed from a rectangular cardbov fnlm*yss0,/i 1d;pqard sheet with a length of 2 meters and a width of 1.2 meters, as illustrated in the diagram below. The box is formed by cutting squares of equal side length ( x meters) from each corner and folding up the sides.

1. Show that the volume of the box can be described by the function $V(x)= 4 x^{3}-6.4 x^{2}+2.4 x $.

2. 1. Find $V^{\prime}(x)$= ax$^2$-bx+c;a=  ,b=  .c=  .
2. Hence or otherwise, find the value for x that maximises the volume of the box;
x=   m
3. Hence, find the maximum volume of the box.

3. Sketch the graph of V(x) on the axes below for the domain 0
4. 1. Write down an integral representing the area between the graph of V(x) and the x -axis;
2. Hence, find this area between the graph of V(x) and the x -axis.

Let A(x) be a function representing the outside surface area of the box.
5. Determine the function A(x) .
A(x)=-ax$^2$+b;a=  ,b=  .
6. Given that the volume of the box is maximised, find the outside surface area of the box.

  All lengths in this questicmr 5s0 9,+nfbe+oea-e0sy .zq g9fbhon are in metres.
Consider the function $f(x)=\sqrt{\frac{16-4 x^{2}}{7}}$ , for $-2 \leq x \leq 2 $. In the following diagram, the shaded region is enclosed by the graph of f and the x -axis.

A rainwater collection tank can be modelled by revolving this region by $360^{\circ}$ about the x -axis.
1. Find the volume of the tank.
V=   m$^3$
Rainwater in the tank is used for drinking, cooking, bathing and other needs during the week.
The volume of rainwater in the tank is given by the function g(t) , for $ 0 \leq t \leq 7$ , where t is measured in days and g(t) is measured in $\mathrm{m}^{3}$ . The rate of change of the volume of rainwater in the tank is given by $g^{\prime}(t)=1.5-4 \cos \left(0.12 t^{2}\right)$ .
2. The volume of rainwater in the tank is increasing only when a 1. Find the value of a and the value of b .
2. During the interval a d=   m$^3$
When t=0 , the volume of rainwater in the tank is 8.2 $\mathrm{~m}^{3}$ . It is known that the tank is never completely full of rainwater during the 7 day period.
3. Find the minimum volume of empty space in the tank during the 7 day period.

V$_{min}$=  m$^3$

  Consider the function defqm,e5h* uz(a9xae) pfined by $f(x)=(1-x) \sqrt{2 x-x^{2}} $ where $0 \leq x \leq 2 $.
1. Show that $ f(1-x)=-f(1+x)$ , for $-1 \leq x \leq 1$ .
2. Find $f^{\prime}(x) $=$\frac{2 x^{2}-a x+b}{\sqrt{2 x-x^{2}}}$;a=   ,b=  .
3. Find the x -coordinates of any local minimum or maximum points.

4. Find the range of f is [-   ,   ]
5. Sketch the graph of y=f(x) , indicating clearly the coordinates of the x -intercepts and any local maximum or minimum points.
6 . Find the area of the region enclosed by the graph of y=f(x) on the x -axis, for $ 0 \leq x \leq 1$ .

  Water is flowing out of a tank at a rate modelled by the functi7udba8j(cvp p jsb6(8on

$R^{\prime}(t)=4 \sin \left(\frac{t}{100}\right)$


Water is flowing into the same tank at a rate modelled by the function

$S^{\prime}(t)=\frac{12 t^{2}}{1+t^{3}}$


Both R^{\prime} and S^{\prime} are measured in $\mathrm{m}^{3}$ , and t in hours for $ 0 \leq t \leq 10$ .
1. Find the interval on which the amount of water in the tank is increasing.

2. Find an expression, T , for the amount of water in the tank at time t if initially there was 25 $\mathrm{~m}^{3}$ of water in the tank.
T(t)=4$\ln \left(t^{3}+1\right)$+400 $\cos \left(\frac{t}{100}\right)$-a; a=  .
3. Hence, or otherwise, find the value of the maximum amount of water in the tank and the time it occurs.