The diagram below shows a circuit connected toy/pyo6hdru/p e/fo c 7l6)l )j an iron rod XY. The connecting wires are flexible. The rod is placed in a magnetic field direp/ /6 r)hyy6c) fjop/ 7oulledcted perpendicularly into the page as shown.


In what direction will the resultant force act on the rod when the current is switched on in the circuit?

  An electron enters a region of magnetic field with a velocity as shown in the diagram. The path followed by the electron is shown by the dotted line. What is the direction of the magnetic field in this region?

  The diagram below shows a circuit connected to an iron rod XY.mhwc15ke1tlyu e9xzdp(k. 22 The connecting wires are flexible. The rod is placed in a magnetic field directed perpendicularly into the page as shown.Two sections of current-carrying wires, X and Y, that lie in t(125t mx2p9ky .ewduzkh1 cl ehe plane of the paper are shown below. The arrow in wire X shows the direction of conventional current. Which response gives possible directions of current in wire Y and electromagnetic force acting on Y?

  A charged particle $x$ enters a region of magnetic field $B$ of $2.0\,T$ with a speed of $3.5\times10^6\,ms^{−1}$ in the shown direction. The magnitude of the charge on the particle is $1.6\times10^{−19}\,C$.



1.Determine whether the particle is positive or negative. Justify your answer.
2.Calculate the magnitude of the force $F$ on this particle when it enters the magnetic field. F =    $\times10^{-12}\,N$

A particle $y$ with an equal but opposite charge enters the same magnetic field $B$ as shown.


3.(1)If the ratio $\frac{v_x}{v_y}=\frac{1}{2}$​, calculate the magnitude of the magnetic force on charge $y$. F =    $\times10^{-12}\,N$
(2)Draw an arrow indicating the direction of the magnetic force on this particle when it just entered the magnetic field.
(3)Particle $y$ has the same mass as particle $x$, draw the path of particle y as it moves through the field.

  A current-carrying wire is at right angles to a uniform magnetic field. The magn50rmcdex+2j c 1eic6plzb2c ;ecc+ripl 6ec; 02bdmcx5z12 e jtic force per unit length on the wire is $\frac{F}{L}$. The length of the wire, the magnitude of the magnetic field strength, and the current of the wire are all doubled. Which of the following is the magnetic force per unit length on the wire after these changes?

  A wire is carrying a cur, 45x+ uxtxebm ubo8n-rent $I$ is placed in a region of uniform magnetic field $B_1$​. The magnitude of the magnetic field is $B$, and its direction is into the page. The force acting on the wire is $F$, as shown in the diagram.


The wire, carrying the same current $I$, is now placed with the orientation shown into another region of uniform magnetic field $B_2$​. The magnitude of the magnetic field is $B$, and its direction is out of the page.

What is the correct direction and magnitude of the force acting on the wire in field $B_2$​?

  The diagram shows a cross sectional view of a current carrying wire. The current direction is out of the plane of the paper.


1.Draw the magnetic field lines due to this wire.
second wire carrying current $B$ is placed near wire $A$.

The current in wire $A$ is $10A$, while in wire $B$ is $12A$. The length of wire $B$ within the magnetic field of $A$ is $1m$.
2.(1)Draw an arrow representing the direction of the force $F$ on wire $B$ due to the magnetic field of wire $A$.
The magnetic field $B$ of wire $A$ can be found using the following formula
$B=\frac{μ_{0}​I_{A}​​}{2πr}$
where $r$ is the distance from the wire.
(2)If the distance between wires $A$ and $B$ is $0.1\,cm$, calculate the magnitude of the magnetic force on wire $B$ due to the magnetic field of wire $A$. State an appropriate unit for your answer. F =    N
3.A third wire $C$ is placed between wires $A$ and $B$.


The total force on wire $C$ due to $A$ and $B$ makes it move to the right as shown.
Determine the direction of the current of wire C. Justify your answer.

  A solenoid is carrying a cucx.o+t 3l 3agsj8rs *:qpv 6varrent of $1.2\,A$ in the shown direction.


1.On the diagram above, draw the magnetic field lines produced due to the current in this solenoid.
A proton moving with speed of $5.6\frac10^6\,ms^{−1}$ is moving in the magnetic field of a different solenoid with an angle $35^{\circ}C$ to the field as shown.


2.(1)Determine the direction of the force on this proton due to the magnetic field of the solenoid.
(2)The magnetic field of the solenoid is $4.2\times10^{−3}\,T$. Calculate the magnitude of the magnetic force on the proton. F =    $10^{-15}\,N$
(3)State and explain the shape of the path that the proton takes as it travels through the field.
(4)Another proton with the same speed enters the same magnetic field as shown.

Discuss whether it will experience the same force as the proton in part b(ii).

  A charged particle is moving horizontally when it enters an electric field between two parallel plates. The path followed by the particle when it passes through the plates is shown. Assume gravitational effects to be negligible.



Which statements are correct about the charged particle?
I. The particle is positively charged.
II. A magnetic field in a direction into the page could cause the charged particles to move horizontally without deflection.
III. A magnetic field in a direction out of the page could cause the charged particles to move horizontally without deflection.

  A mass spectrometer is a tool that uses a magnetic field to determine the mass of a moving charged particle.
An alpha particle with a speed of $2.0\times10^7\,ms^{−1}$ enters a region of magnetic field directed into the plane of the paper.

(1)Suggest why the alpha particle undergoes circular motion inside the magnetic field.
(2)Explain why the centripetal force does no work on the alpha particle.
2.(1)On the diagram, draw an arrow to represent the path of the alpha particle inside the magnetic field.
(2)State the charge on the alpha particle.
(3)The radius of the path of the alpha particle is determined to be $15\,cm$, and the magnetic field strength is $2.77\,T$.
Calculate the mass of the alpha particle, expressing your answer to the appropriate number of significant figures. m =    $\times10^{-27}\,kg$

  

  
An alpha particle of mass $m$ and charge $q$, is accelerated through a potential difference $V$ into a magnetic field of flux density $B$ that is at right angles to the direction of motion. Which of the sketches below best describes the relationship between the radius of path $r$ and the potential difference of the accelerating field?

  A source of radiation is near a magnetic field that is directed into the page. A sheet of paper is placed in the path of the radiation before it enters the magnetic field.


The gamma radiation is not deflected when entering the magnetic field. Which of the following is correct about the other type of radiation that penetrates the paper sheet and the direction of its deflected path in the magnetic field?

  An object of mass $m$ and charge $q$ is dropped vertically between two parallel plates, $K$ and $L$. A magnetic field $B$ can be created perpendicular to the plane of the paper. The electric field between plates is $E$.


Which of the following is correct about the magnitude of magnetic and electric fields when the object falls vertically at a constant velocity $v$?