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习题练习:Models of Matter A.5 ldeal Gases



 作者: admin发布日期: 2024-02-05 13:08   总分: 12分  得分: _____________

答题人: 匿名未登录  开始时间: 23年12月20日 21:12  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  For a fixed mass of gas at a conu h* hf6kdsmmg98 xb9:c c,bt,stant temperature, what happens to the volume if the pressure of the gas i9x,h bt c6ks:mg8f*, d9c mhubs doubled?

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2#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Which of the followingxvl5,pk3,v gw2n0cqmrp2v p (d*j )gr conditions makes gases deviate from ideal behavior?

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3#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Based on the graph below, choose the correct statement that describes de ezz))t)jyj:d , *pythe relatiot e)yjzezdjp * :),y)dnship between pressure and temperature for a fixed mass and volume of a gas?


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4#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The ideal gas equation is a formula that combines the relationship 6ryh,p ;,mnz rbetween pressure, volume, temperature, and the numbenr rh,p y6,mz;r of moles.
1.Complete the table below by calculating the missing variables of the ideal gas equation.
P V n T
  $\times10^4$Pa $0.015m^3$ 0.400mol $37^{\circ}C$
152,000Pa   $m^3$ 2.00mol 298.15K
31,000Pa $0.25m^3$   mol 271.15K
250kPa $0.75dm^3$ 0.580m0l   k
2.A $256cm^3$ flask contains 0.800g of a gaseous compound with an empirical formula of CHCl. The pressure and the temperature of the gas are respectively $10^5$, Pa10 and 373K. Determine the molecular formula of the compound.

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5#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Liquid butanol $(C_4H_9OH)$ burns or combusts in oxygen to produce $CO_{2(g)}$ and $H_2O$(g).
1.Write a balanced equation, including state symbols, for this reaction.
2.When $1.250cm^3$ of butanol is combusted in excess oxygen,$1.921dm^3$ of water vapor is collected at a pressure of 125.0 kPa and $150.0^{\circ}C$. Calculate the moles of butanol that were combusted.  mol
3.Determine the density of liquid butanol in $g\:cm^{-3}$.  g $cm^{-3}$

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6#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Based on the table below, what is,tcsddm qx:g,8 +5 cfs the correct calculation to determine the final volume of a fixed mas,,dscxg m8 fct:+5dqs s of gas:
Initial Final
Pressure = 1.00 atm Pressure = 1.60 atm
Temperature =$20^{\circ}C$ Temperature =$10^{\circ}C$
Volume =$5.00dm^3$ Volume = ?


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7#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Automobile airbags are inflated1w5gk:jlu2 4wryp3e.j /ltpv with $N_2$, a byproduct of sodium azide decomposition, according to the following reaction.
$2NaN_{3(s)}\rightarrow2 Na_{(s)}+3N^{2(g)}$
Calculate the mass (in grams) of sodium azide needed to generate $0.07m^3$ of $N^2$ at $1.01\times10^{5}Pa$ and $26.0^{\circ}C$.$n_{N2}$=  mol, mass of $NaN_3$=  g

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8#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  14.01g of nitrogen gawb9) cttb-xy nx, e1.g0r6xc os $(N_2)$ is reacted with excess $H_2$. What volume of ammonia $(NH_3)$gas would be produced at STP? The molar volume of a gas at STP is $22.7dm^3$.
$N_{2(g)}+3H_{2(g)}\rightarrow2NH_{3(g)}$

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9#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Sodium azide is an ionic compound xy s02d8kdg;l found within the airbags of some older cars. The airbag is deployed as a safety feature in the event of an accident. In this application ;k8dyd2 l0xgs, the sodium azide decomposes rapidly, and the gas formed inflates the airbag.
The decomposition of sodium azide under these conditions is given below.
$2NaN_{3(s)}\rightarrow2Na (s)+3 N_{2(g)}$
1.Suggest the formula and charge for the azide ion.
2.A typical airbag requires $65.0dm^3$of nitrogen gas for complete inflation at STP. Using section 2 of the data booklet, calculate the mass of sodium azide that the airbag must contain for this purpose.Molar mass for sodium azide calculated=  $g mol^{-1}$

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10#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Which of the following gases most closely aligns with the be -huf8sm h-f(khavior of an ideal gas-fuh8m- hk (sf?

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11#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Under which conditions would s7*, wjivmz3oi40oz ibxf fput1;g; 5a gas deviate the most from the ideal gas model?

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12#
 
单选题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A sample of gas at a c-c 9j) ojd;qfzertain temperature, pressure, and volume $(T_1,P_1,and V_1T)$ undergoes a change in temperature and pressure $(T_2andP_2)$.What is the new volume $(V_2)$?
Before: $T_1,P_1,V_1$;
After: $P_2=2P_1$ AND $T_2=\frac{1}{2}T_1$

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