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习题练习:IB MAI HL Calculus Topic 5.3 Kinematics



 作者: admin   总分: 14分  得分: _____________

答题人: 匿名未登录  开始时间: 24年03月22日 14:37  切换到: 整卷模式

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1#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  The graphs of displacement, velocity and acceleration of a roller p+c 7 6i0xuwwevpi8d1coaster in a theme park are shown in the foi1wux6w87p v +0i pecdllowing diagram.


1. Complete the following table by noting which graph A, B or C corresponds to each function.

When function is displacesment ;the graph is  
When function is acceleration ;the graph is   .
2. Write down the value of t when the velocity is greatest.
t=  .

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2#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A squirrel is climbing p 6eb h;b6p*b( n8efkua tree with velocity $v \mathrm{~ms}^{-1}$ for 9 seconds. This is shown in the graph below.

1. Write down the squirrel's velocity at t=4 .
V(4)=  m/s
2. Find the squirrel's acceleration at t=2 .
m=  m/s
3. Find the total distance travelled by the squirrel.
d=  m

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3#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  An object is moving along a straight line from a point $\mathrm{P}$ . The velocity v , in $\mathrm{m}$ $\mathrm{s}^{-1} $, is given by the function v(t)=2-$e^{-\sin t^{3}}$ where t \geq 0 is measured in seconds.
1. Write down the first two times $ t_{1}$, $t_{2}>0$ when the object changes direction.
t≈   and 1.77 sec
2. 1. Find the time 0
2 . Find the time 0
3. Find the distance travelled by the object between times t=$t_{1}$ and t=$t_{2}$ .
d   m (four decimal places)

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4#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  An object is moving along a straigj.jmv n)vp4dhb-; 3c8vv 2uyk ht line such that its velocity, v, $\mathrm{~ms}^{-1}$ , is given by $v(t)=5 t e^{-1.2 t}$ , for $t \geq 0 $.(two decimal places)

1. On the grid below, sketch the graph of v , for $0 \leq t \leq 3$ .

2. Find the distance travelled by the object in the first 3 seconds.
d=  m
3. Find the velocity of the object when its acceleration is zero.
v(0.833)=  ms$^{-1}$

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5#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A particle is moving o3uxs:* iz.boc. j c,zh70 kvialong a straight line. Its velocity can be modelled by the functionx:0 hiosuji.zzcv 3c.b*k 7o, v(t)=$2 t-0.3 t^{3}+2$ , for $t \geq 0 $, where v is in $\mathrm{ms}^{-1}$ and t in seconds.
1. Find the acceleration of the particle after 2.2 seconds.
a(2.2)=-   ms${-2}$.
2. 1. Find the time when the particle's acceleration is zero.
t=  s
2 . Find the particle's velocity when its acceleration is zero.
v(1.49)=   ms${-1}$.

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6#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A particle P starts from a fixed point O and moves along a hoch;4 jrhy x8xxc/c+rb 1u,1agg9x-wtrizontal straight line. Its velt aub-81xx/g+ ;4gyc hrxh19w cj,cxrocity v $\mathrm{~ms}^{-1}$ after t seconds is given by



The following diagram shows the graph of v .

1. Find the initial velocity of P .
v(0)=  ms$^{-1}$
2. Find the acceleration of P during the first second.
a=  ms$^{-2}$.
3. Write down the number of times the particle changes direction in the first 8 seconds. Justify your answer.
4. Find the total distance travelled by the particle in the first 8 seconds.
d=  m .

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7#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A drone moves in a straight line and zhu 3xex)i8 4.r+mgh-iqb v9 uits velocity, $v \mathrm{~ms}^{-1}$ , at time t seconds, is given by v(t)=$\left(t^{2}-2\right)^{2}$ , for $0 \leq t \leq 2 $.
1. Find the initial velocity of the drone.
v(0)=  ms$^{-1}$
2. Find the value of t for which the drone is at rest.
3. Find the total distance travelled by the drone in the first 2 seconds.
d=  m
4. Show that the acceleration of the drone is given by a(t)=$4 t^{3}-8 t $.
a(t)=at$^3$-bt; a=  ,b=  .
5. Find the values of t for which the velocity is positive and the acceleration is negative.

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8#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A freight lift moves along a vertical straight line so that its(4uht ypg u.ap)hzn(8 velocity, v \mathrm4(hu.8g(np a uz)hpt y{~ms}^{-1} , after t seconds is given by v(t)=$1.5^{t}-4.9$ , for $0 \leq t \leq 6$ .
1. Find when the lift is at rest.
t=  s.
2. Find the acceleration of the lift when t=3 .
a(3)=  ms${-2}$
3. Find the total distance travelled by the lift.
d=   m.

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9#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A particle P moves alonces8 kt(;yi/g6b.jo p p6-xrvj/j rx .g a straight line so that its velocity, $v \mathrm{~ms}^{-1}$ , after t seconds, is given by $v=\sin 3 t-2 \cos t-2$ , for $0 \leq t \leq 6$ . The initial displacement of P from a fixed point O is 5 metres.
1. Find the displacement of P from O after 6 seconds.
s=-  m ; (two decimal places)
The following sketch shows the graph of v .

2. Find when the particle is first at rest.
t=  s; (two decimal places)
3. Write down the number of times the particle changes direction.
hence    time(s)
4. Find the acceleration of P after 2 seconds.
a(2)=   ms$^{-2}$.(two decimal places)
5. Find the maximum speed of P .

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10#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  Note: In this question, distance is in metre )uo-c qxfw:3pxwk ,t(s-v8kl s and time is in seconds. An experiment in a particle accelerator moves a particle P in a straight line for six seconds. Its acceleration during this xft 8,( o-ks c-q kvw:)xpu3wlperiod is given by a(t)=-$2 t^{2}+13 t-15 $, for $0 \leq t \leq 6$ .
1. Write down the values of t when the particle's acceleration is zero.
t=  and 5.
2. Hence or otherwise, find all possible values of t for which the velocity of P is increasing.

The particle has an initial velocity of $7 \mathrm{~ms}^{-1}$ .
3. Find an expression for the velocity of P at time t .

4. Find the total distance travelled by P when its velocity is decreasing.
d=  m

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11#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A remote-controlled car C i*c.,p qs3 neoqs moving along a straight path so that its velocity, v, e p,3n.cq o*sq$\mathrm{~ms}^{-1}$ after t seconds, is given by v=$2 \sin t-\cos 5 t+0.1$ , for $0 \leq t \leq 4 $. The initial displacement of C from a fixed point O is 2 metres.

1. Find the displacement of C from O after 4 seconds.
s=  m.
2. Find the second time for t , when the particle is at rest.
t=  s.
3. Write down the number of times C changes direction.
4. Write down the number of times C is neither accelerating or decelerating.
5. Find the maximum distance of C from O during the time 0 \leq t \leq 4 and justify your answer.
d$_{max}$=  m

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12#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  John drops a stone from the t6re+m1vj6r1: yc zqcnop of a cliff which is h metres above sea level. The stone strikes the waer:1+ yjc qmv66n rcz1ter surface after 9 seconds.
The velocity of the falling stone, $v \mathrm{~m} \mathrm{~s}^{-1}$, t seconds after John releases it, can be modelled by the function(round number)



1. Find the velocity of the stone when t=12 , giving your answer to the nearest $\mathrm{m} \mathrm{s}^{-1}$ .
v(12)≈   ms$^{-1}$.(round number)
2. Calculate the value of h , giving your answer to the nearest metre.
h≈   m,(round number).
The velocity of the stone when it reaches the bottom of sea is $10 \mathrm{~m} \mathrm{~s}^{-1}$ .
3. Determine the depth of sea near the cliff, giving your answer to the nearest metre.
d≈   m.

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13#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  An object moves in a straight linp+mk5grp ; ncpf).u;fe such that its velocity, v \mathrm{~m} \mathrm{~s}^{-1} , at time t seconds, is given by


1. Find the value of t , for t>0 , when the object is instantaneously at rest.
t=  s.
The object returns to its initial position at t=T .
2. Find the value of T . Give your answer correct to three significant figures.
T≈  s.(one decimal place)

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14#
 
填空题 ( 1.0 分) 切至整卷模式 搜藏此题  
  A particle moves along the x -2tmff)bz 8c4yj* hl1taxis so that its velocity, $v \mathrm{~m} \mathrm{~s}^{-1}$ at time t seconds, is given by the equation

$v(t)=10 e^{-\frac{t}{4}}-5$

1. Find the time at which the particle changes direction.
The particle changes direction after approximately (  .77) seconds.
2. Find the magnitude of the particle's acceleration at time t=2 seconds.

The particle starts from the origin O .
3. Find an expression for the displacement of the particle from $\mathrm{O}$ at time t seconds.
$s(t)=a-b e^{-\frac{t}{4}}-c t$ ; a=  ,b=  ,c=  .
4. Find the time at which the particle returns to the origin.
5. Calculate the total distance travelled by the particle by the time it has returned to the origin.
the time the particle has returned to the origin, it has travelled approximately (  .3) metres.

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