John drops a stone from the t
6re+m1vj6r1: yc zqcnop of a cliff which is h metres above sea level. The stone strikes the wa
er:1+ yjc qmv66n rcz1ter surface after 9 seconds.
The velocity of the falling stone, $v \mathrm{~m} \mathrm{~s}^{-1}$, t seconds after John releases it, can be modelled by the function(round number)
1. Find the velocity of the stone when t=12 , giving your answer to the nearest $\mathrm{m} \mathrm{s}^{-1}$ .
v(12)≈
ms$^{-1}$.(round number)
2. Calculate the value of h , giving your answer to the nearest metre.
h≈
m,(round number).
The velocity of the stone when it reaches the bottom of sea is $10 \mathrm{~m} \mathrm{~s}^{-1}$ .
3. Determine the depth of sea near the cliff, giving your answer to the nearest metre.
d≈
m.