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习题练习:SL/HL Topic C1.1 Enzymes and metabolism



 作者: admin   总分: 16分  得分: _____________

答题人: 匿名未登录  开始时间: 25年01月31日 10:44  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 1 题组 (共 4 题 4 分)
  1. How is reliability established in an enzyme experim)2xs naj9)v ))3fwywb ck3crqa8: kkjent?

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2#
 
单选题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
  2. What can cause an enojgs5+1lv4.z 0 -u;+blf / nfbzgtgcuzyme to be denatured?

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3#
 
单选题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
  3. Which of the following correctly descrm2jpd fg c,-v,ibe aspects of a metabolic pathway?
I. It is regulated by one enzyme.
II. It is a series of reactions to produce an end product.
III. It is a system producing energy.
IV. It can be anabolic or catabolic in nature.

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4#
 
单选题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
  4. The binding of the substrate to the active site of an enzyme causes6fize3 :r8hoem2/ ofr which of the following:m8ir 6/rhee 3 fzf2oo changes?
I. A change in the shape of the active site.
II. A change in the shape of the substrate.
III. A lowering of the activation energy of the reaction.
IV. The denaturation of the enzyme.

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5#
 
问答题 ( 1.0 分) (组内1/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第1/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
I. Explain why glucose is formed in thex h14uz pn8qq; reaction mixture.
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6#
 
问答题 ( 1.0 分) (组内2/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第2/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
II. List two variables thw;ng z3lifejn *7yea.zng2) *at should be controlled in this experiment, other than those l*wizfnz*;g a)23en7g.yjen given.
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7#
 
问答题 ( 1.0 分) (组内3/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第3/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
III. Does the data cic jzg(4j) n02f, mlhpu u.,byollected indicate that the rate of the reaction is constant in4yu (ihj0jg un)cl., zbmp2 f, the first 3 minutes?
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8#
 
问答题 ( 1.0 分) (组内4/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第4/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
IV. Calculate the rate of reaction in the first 5 minute osv,in2.g l)zs
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9#
 
问答题 ( 1.0 分) (组内5/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第5/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
V. Describe the changes in d4 k olvs9b0)plw9cfvt3m2z:the rate of reaction from the $4^{th}$ to the $8^{th}$ minute.
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10#
 
问答题 ( 1.0 分) (组内6/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第6/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VI. Why was it not necessary to collect duh9xw9xhy ry3 91jt i+o ka/3qata after the $8^{th}$ minute?
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11#
 
问答题 ( 1.0 分) (组内7/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第7/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VII. Predict, with a reason, the fructose concentration inn* 5e+boof8fve xyt7w:5xj 25 bg+p6fywv g8l the reaction mixture at the tp2olfv5 b:ej75+wyg8y vnf b8x6* ofw5xg e +$6^{th}$ minute.
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12#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 3 题组 (共 1 题 1 分)
6. Enzymes are specific to a particular reaction. Explain why enzyme spc1a zwqhv e ,+no60un)ecificity is important in the control of n o6qhw au,+vzn01)ecmetabolic pathways.
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13#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
I. Penicillin does not affect humv /w61fgqo)3tcus6vzre: y- san enzymes.
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14#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
II. Penicillin is a permanent competitive inhibic,0 wfpzk7e chh;*v 8ltor of transpeptidase.
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15#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
III. Suggest how penicillin resistance has developed in some bacteria.y* k b0.rq,+ kc,3vxndiu*ri p
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16#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
8. ATP is an allosteric inhibitor of phosphofructokina -xruntu vj/)6se and pyruvate kinase, two enzymes involved in glycolysis. Discuss the importance of feedback inhibition of metabolic pathways in biological systems using this tjvxn- r/u) 6uas an example.
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